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jolli1 [7]
3 years ago
12

Hellllllllllpppppppppp please​

Mathematics
1 answer:
baherus [9]3 years ago
5 0

Answer:

jkggkjhcghfgyhgdf

Step-by-step explanation:

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Please hurry! This is due soon.
kotykmax [81]

Hi!

We can see here that this is a composition question.

And since the composition of g of f of x is x, we can conclude that g(x) is the inverse of f(x) (if you're confused, search up the definition of an inverse function).

To find an inverse function, we can take the f(x) function and change the positions of the x and y variables.

f(x)=\frac{e^7^x+\sqrt{3}}{2}

y=\frac{e^7^x+\sqrt{3}}{2}

x=\frac{e^7^y+\sqrt{3}}{2}

2x=e^7^y+\sqrt{3}

e^7^y=2x-\sqrt{3}

7y=ln(2x-\sqrt{3})

y=\frac{ln(2x-\sqrt{3})}{7}

Which is answer choice A, to check your work, you can solve the composition of g(f(x)), which will get you x.

g(f(x))

g(\frac{e^7^x+\sqrt{3}}{2})

\frac{ln(2(\frac{e^7^x+\sqrt{3}}{2})-\sqrt{3}}{7}

2s cancel.

\frac{ln(e^7^x+\sqrt{3})-\sqrt{3}}{7}

The natural log and e cancel.

\frac{7x+\sqrt{3}-\sqrt{3}}{7}

\sqrt{3}s cancel.

\frac{7x}{7}

7s cancel.

x

Hope this helps!

3 0
2 years ago
In Ms. Perron's class, 75% of the studnetw are doys. There are 18boys in the class. What is the totla numder of students in Ms.
Anastasy [175]
Your answer should be 24
6 0
3 years ago
True of false !!! The triangle shown below must be congruent
user100 [1]

False.

Right triangles do not have to be congruent.

:)

6 0
2 years ago
Read 2 more answers
HElp 64 points and Brainlyiest to who ever can solve the problem question on the picture
andrew11 [14]

Answer:

Addition Property of Equality

Step-by-step explanation:

You are adding 3/4 to both sides to isolate the <em>x</em>.

4 0
3 years ago
5x^{4}-7x^{3}-5x^{2}+5x+1-0
den301095 [7]

Answer:

5x^4 -7x^3-5x^2+5x+1

Step-by-step explanation:

Hey!

You would just add all the numbers up, and by making sure that you combine all like terms. In this case it is just 1-0 = 1 and so the solution would be the same as your question but with a 1 and you would get rid of the -0.

Hope this helps!

7 0
2 years ago
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