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Natalka [10]
3 years ago
14

A glider is gliding at an altitude of 265 ft. An airplane is flying at an altitude of 35,775 ft. How many times higher is the ai

rplane than the​ glider? How many times higher would the airplane be than the glider if the altitude of the glider was only 135 ft​?
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

If a glider has a 50:1 glide ratio, then it travels 50 feet for every foot of altitude lost. Glide rati

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For question 3, is it right though? Thankss
pishuonlain [190]

Yes it is correct, 7/12 is the equivalent to C. 7 divided by 12

8 0
3 years ago
an original piece of artwork is 3 feet by 2.5 feet. A reprint of the artwork is 6 inches by 5 inches. Are the pieces similiar? I
amid [387]

Answer:

Yes

Explaination:

They are similar and the ratio is still the same. The artwork's shape didn't change we just resized it by multiplyting its length and width by 2.

6 0
3 years ago
Paid $1,000 in interest on a loan of $10,000 for a
Lorico [155]

Answer:

R = 2 % per annum.

Step-by-step explanation:

SI = (P*T*R) /100

$1000 = ($10000 * 5 yrs *Rate) /100

4 0
3 years ago
23. Eduardo wants to get a grade of 95 in his math
dem82 [27]

Answer:

105

Step-by-step explanation:

It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

(91+89+X)/3 =95

 91+89+X =95*3

180+X =285

X =285 - 180

  =105

7 0
3 years ago
A city averages 14 hours of daylight in June (the longest days) and 10 in December (the shortest days). Assume that the number o
UNO [17]

The equation is given as

y = 12 sin (6t - \pi /2) + 2

<h3>The Amplitude </h3>

The Amplitude can be calculated as

amplitude = \frac{max + min}{2}\\ amplitude = \frac{10+14}{2} = 12

<h3>The Vertical Shift</h3>

The vertical shift is the average difference between the maximum and minimum.

Vertical Shift = \frac{Max - Min}{2} = \frac{14-10}{2} = 2

For b value

The Time Period will be twice the distance between max and min.

time period = \frac{2\pi }{b} \\time period = 2 * distance between max and min\\b = \frac{2\pi }{2}*\frac{1}{b} = \frac{\pi }{6}

<h3>The Period</h3>

The period is calculated as

T = \frac{2\pi }{b} \\T = \frac{2\pi }{\frac{\pi }{b} } = 12

The equation is given as

y = 12 sin (6t - \pi /2) + 2

Learn more on time period and amplitude here;

brainly.com/question/15531840

8 0
2 years ago
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