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Phantasy [73]
1 year ago
14

Consider this quadratic equation. x2 3 = 4x which expression correctly sets up the quadratic formula to solve the equation?

Mathematics
1 answer:
son4ous [18]1 year ago
4 0

The expression which correctly sets up the quadratic formula to solve the equation is (A) \frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}.

What is an expression?

  • In mathematics, an expression is a combination of numbers, variables, and functions (such as addition, subtraction, multiplication or division, etc.)
  • Expressions are similar to phrases.
  • A phrase in language may comprise an action on its own, but it does not constitute a complete sentence.

To find which expression correctly sets up the quadratic formula to solve the equation:

Theory of quadratic equation - A quadratic equation is defined as any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power.

An example of a quadratic equation in x is -4x^{2} +4=9x.

How to solve any quadratic equation using the Sridharacharya formula?

Let us represent a general quadratic equation in x, ax^{2} +bx+c=0 where a, b and c are coefficients of the terms.

According to the Sridharacharya formula, the value of x or the roots of the quadratic equation is -

x=\frac{-b+-\sqrt{(b)^{2}-4(a)(c) } }{2a}

The given equation is x^{2} -4x+3=0

Comparing with the general equation of quadratic equation, we get a = 1, b = -4 , c = 3.

Putting the values of coefficients in the Sridharacharya formula,

\frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}  which is (A).

Therefore, the expression which correctly sets up the quadratic formula to solve the equation is (A) \frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}.

Know more about expressions here:

brainly.com/question/22048677

#SPJ4

The complete question is shown below:

Consider this quadratic equation. x^2+3=4x. Which expression correctly sets up the quadratic formula to solve the equation?

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Step-by-step explanation:

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Hey there!

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