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Sliva [168]
3 years ago
14

Can someone help me solve D, a, or/and b

Mathematics
1 answer:
Margaret [11]3 years ago
4 0

Answer:

slop = (175 - 125) \div (2 - 1) = 50 \\ y - 125 = 50 \times (x - 1) \\ y = 50x - 50 + 125 \\ y = 50x + 75

you can solve problems by this equation

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Answer:

a=13m

Step-by-step explanation:

that's it in the picture

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You know 13 + 7 = 20. Therefore 13+ 7 + 2 = 20 + 2
omeli [17]

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Step-by-step explanation:

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What is 300% of 3?<br> A) 0.09 B) 0.9 C) 9 D) 900
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In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

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Step-by-step explanation:

Given:

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Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

7 0
3 years ago
Given each set of points, determine if AB and CD
tester [92]

Answer:

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