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tankabanditka [31]
3 years ago
15

3/5+1/4= cuanto es el resultado?​

Mathematics
2 answers:
NARA [144]3 years ago
7 0

Answer:

= \frac{17}{20}

= \frac{3 \times 4}{5 \times 4}  +  \frac{1 \times 5}{4 \times 5}

=  \frac{12}{20}  +  \frac{5}{20}

=  \frac{12 + 5}{20}

=  \frac{17}{20}

ella [17]3 years ago
6 0

Answer:

17/20

Step-by-step explanation:

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Answer:

Step-by-step explanation:

pitch=4/12=1/3

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Please someone help me. Thank you.​
KiRa [710]

Answer:

Step-by-step explanation:

take x degree as reference angle

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3 0
3 years ago
Solve <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x-10%7D%7B4%7D" id="TexFormula1" title="\frac{2x-10}{4}" alt="\frac{2x-10}{4}
GREYUIT [131]
X = -1!
1. Factor out 2 from the expression : 2(x-5) / 4 = 3x
2. Reduce the fraction with 2 : x-5 / 2 = 3x
3. Multiply both sides of the equation by 2 : x-5=6x
4. Move the terms : x - 6x = 5
5. Collect like terms : -5x = 5
6. Divid both sides by -5
Hope this helps!
8 0
3 years ago
What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
3 years ago
Which of the equations is proportional if y is a function of X?
Taya2010 [7]

Answer:

y=4x

Step-by-step explanation:

it goes through 0,0 on my graph

6 0
3 years ago
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