Answer:
Step-by-step explanation:
the slope would be y2-y1/x2-x1
so the distance is y and the time is x so what you are going to do is 30-18 over 5-3 which then means it would be 12/2 which equals 6
Answer:
ΔT = ΔT0 e^-K T
As I understand Newton's Law of Cooling
ΔT at any time is the difference between the temperature and the surroundings
Originally ΔT0 = 95 - 22 difference between 95 and room temperature
65 - 22 = 33 = 73 e^-KT where t is time to cool to 65 deg
ln (33/73) = -KT K = .794 / 5 = .159 where 5 is time to cool to 65 deg
40 - 22 = 73 e^-.159 T where t is time to cool to 40 deg
18 = 73 e^-.159 T
ln (18 / 73) = -.159 T
T = 8.8 min
It would take 8.8 min for the object to cool to 40 deg C
Suppose the object cooled from 95 to 90 deg, then
ln 68 / 73 = -.159 T and T = .45 min
No, he needs to do 5(to the power of 2) plus 3(to the power of 2)
this should give him 25 plus 9 = 34
Answer:
1.12
Step-by-step explanation:
7, 5, 1, 6, 2 Mean Absolute Deviation = 2.16
3, 6, 3, 2, 1 Mean Absolute Deviation = 1.2