Question

pratap puri rowed 26 miles down a river in 2 hours, but the return trip took him 6 1/2 hours. find the rate pratap can row in still water and find the rate of the current. Let x= rate Pratap can row in still water and y=rate of the current

Answer 1

The rate of current will be "4.5 mph" and the rate Pratap can row in still water will be "8.5 mph".

Given:

• Distance "26 miles" in time "2 hours".

Let,

• Speed of water = y
• Pratap speed when rowing in still water = x

As we know,

→ $Speed = \frac{Distance}{Time}$

then,

→ $x+y = \frac{26}{2}$

→ $x+y = 13$

→       $x = 13-y$

In return trip took him time "6.5 hours",

→ $x -y =\frac{26}{6.5}$

→ $x -y = 4$

By substituting the value of "x", we get

→ $13-y-y=4$

      $13-2y=4$

              $2y= 13-4$

                $y = \frac{9}{2}$

                   $= 4.5 \ mph$ (Rate of the current)

By substituting the value of "y", we get

→ $x = 13-a$

   $x = 13-4.5$

      $= 8.5 \ mph$ (Pratap can row in still water)

Thus the above answer is correct.

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