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3 years ago

SOMEONE PLEASE HELP QUICK

Mathematics

1 answer:

Viktor [21]3 years ago

4 0

X can be any number in the graph as long as it is on the x-axis therefore you can put x as -1,0 and 1. Then you would need to replace the ‘x’ in the equation so it would look like y=-2*1+3. You replace ‘x’ with every number you put in the x boxes. Then just solve the equations

y=-2*1+3
Y=-2*0+3
Y=-2*-1+3
They would give you the y axis coordinates so then you just put them together for the middle column.

Answer

y=-2*1+3=1
Y=-2*0+3=3
Y=-2*-1+3=5

Coordinates are (1,3) (0,3) (-1,5)

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Rose and Andrew are financing 128,000 to purchase a condominium. They obtained a 15 year fixed rate loan with a rate of 5.05%. T

anzhelika [568]

Amount Financed(P) = $ 128,000

Time = 15 year

Rate of interest= 5.05%

Amount after 15 years translates to,

${\text{Using the formula}} P(1+\frac{R}{100})^n\\\\ 128,000(1 +\frac{5.05}{100})^{15}\\\\ =128,000 \times (1.0505)^{15}\\\\=128,000 \times 2.0938\\\\=268,009.890$

Rose and Andrew has taken four points to lower their rate to 4.81% .

Amount after 15 years translates to, if rate of interest is 4.83 %

${\text{Using the formula}} P(1+\frac{R}{100})^n\\\\ 128,000(1 +\frac{4.83}{100})^{15}\\\\ =128,000 \times (1.0483)^{15}\\\\=128,000 \times 2.0290\\\\=259713.0404$

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= $8296.8496

3 0

3 years ago

I) Find the volume in terms of pie

SVETLANKA909090 [29]

Answer:

i) pi×4500 cm³

ii) pi×600 cm²

iii) 14 liters

Step-by-step explanation:

in general : the diameter is 30 cm, the radius is half of that (15 cm)

the volume of a cylinder is base area times height.

Vc = pi×r²×h = pi×15²×20 = pi×225×20 = pi×4500 cm³

ii)

similar to volume, the side "mantle" area of the cylinder is the circumference of the base area times height.

surface area of the cylinder mantle is

Scm = 2×pi×r×h = 2×pi×15×20 = pi×30×20 = pi×600 cm²

iii)

for this we need now to do the multiplication with pi and then convert the cm³ to liters.

1 liter = a cube of 10 cm side length = 10×10×10 = 1000 cm³

pi×4500 = 14137.17 cm³ = 14.13717 liters or rounded 14 liters

3 0

3 years ago

Okay now using distributive property write 2(4x-9) without parenthesis

riadik2000 [5.3K]

2(4x - 9) =
2 * 4x - 2 * 9 =
8x - 18

Hope this helps!!
~Kiwi

6 0

2 years ago

What is (64x^2y^3)-1/2 as radical expression?

oksano4ka [1.4K]

Answer:

$\frac{1}{8xy \sqrt{y} }$

Step-by-step explanation:

$(64 {x}^{2} {y}^{3} )^{ - \frac{ 1 }{2} } \\ \\ = \frac{1}{(64 {x}^{2} {y}^{3} )^{\frac{ 1 }{2} } } \\ \\ = \frac{1}{ \sqrt{64 {x}^{2} {y}^{3}} } \\ \\ = \frac{1}{ \sqrt{ {(8xy)}^{2} y} } \\ \\ = \frac{1}{8xy \sqrt{y} }$

3 0

2 years ago

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$

Imaginary part of the above =0

i.e. $\sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1$

So the value of alpha = $-3+i\sqrt{3} , 1+\sqrt{3}$

3 0

3 years ago