All categories

3 years ago

SOMEONE PLEASE HELP QUICK

Mathematics

1 answer:

Viktor [21]3 years ago

4 0

X can be any number in the graph as long as it is on the x-axis therefore you can put x as -1,0 and 1. Then you would need to replace the ‘x’ in the equation so it would look like y=-2*1+3. You replace ‘x’ with every number you put in the x boxes. Then just solve the equations

y=-2*1+3
Y=-2*0+3
Y=-2*-1+3
They would give you the y axis coordinates so then you just put them together for the middle column.

Answer

y=-2*1+3=1
Y=-2*0+3=3
Y=-2*-1+3=5

Coordinates are (1,3) (0,3) (-1,5)

You might be interested in

In the X Y -plane, Line crosses the Y - axis at the point (0,3) and passes through the point ( 4,5). Which of the following is a

nikitadnepr [17]

Answer: y = 1/2x + 3

Step-by-step explanation:

Use the equation y=mx +b

Find the slope (m) of the line by finding the difference in y over the difference in x. Or "rise over run".

The y-intercept (b) is 3 (when x is zero, it is y).

4 0

3 years ago

A grocery store will only accept yellow onions that are at least 3 inches in diameter. A grower has a crop of onions with diamet

Marizza181 [45]

<span>For the answer to the question above,this is a simple question.

z = (3.25-3.5)/.25= -1
p= .8413
then multiply 100 to get the percentage.
The answer will be
84.13% or 84% rounded to the whole number.
I hope my answer helped you with your problem above. Have a nice day</span>

5 0

3 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

A bug completes one lap along the edge of a circular planter of radius 11.7 cm in 13.91 s. How fast was it traveling? 1. 10.8518

IrinaK [193]

Answer:

8.5.28492 cm/s

Step-by-step explanation:

We are given that

Radius of circular planter=11.7 cm

Time taken by bug =13.91 s

We have to find the speed of bug.

We know that

Speed = $\frac{distance}{time}$

Distance traveled by bug = $2\pi r$

Distance traveled by bug = $2\times 3.14\times 11.7$

Because $\pi=3.14$

Speed of bug= $\frac{2\times 3.14\times 11.7}{13.91}=5.28224 cm/s$

Hence, speed of bug=5.2822 4 cm/s

Answer:8.5.28492 cm/s

8 0

3 years ago

8 freshmen, 9 sophomores, 9 juniors, and 7 seniors are eligible to be on a committee.

loris [4]

Answer: 11113200

Step-by-step explanation:

We know that , the number of combination of choosing r things from n things is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

$^8C_4\times ^9C_5\times^9C_2\times^7C_3$

$=\dfrac{8!}{(8-4)!4!}\times\dfrac{9!}{(9-5)!5!}\times\dfrac{9!}{(9-2)!2!}\times\dfrac{7!}{3!(7-3)!}\\\\ =\dfrac{8\times7\times6\times5\times4!}{4!4!}\times\dfrac{9\times8\times7\times6\times5!}{4!5!}\times\dfrac{9\times8\times7!}{7!2!}\times\dfrac{7\times6\times5\times4!}{3!4!}\\\\=11113200$

∴ The number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors = 11113200

6 0

3 years ago