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sdas [7]
2 years ago
13

Solve the given proportion for x.  Answer to two decimal places. x/5=16/21​

Mathematics
2 answers:
Anarel [89]2 years ago
5 0

Step-by-step explanation:

\frac{x}{5}  =  \frac{16}{21}  \\ by \: cross \: multiplication \\ x \times 21 = 5 \times 16 \\ 21x = 80 \\ x =  \frac{80}{21}  \\ x = 3.8

Angelina_Jolie [31]2 years ago
3 0

\\ \sf\longmapsto \dfrac{x}{5}=\dfrac{16}{21}

\\ \sf\longmapsto 21x=16(5)

\\ \sf\longmapsto 21x=80

\\ \sf\longmapsto x=\dfrac{80}{21}

\\ \sf\longmapsto x=3.6

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Posing A(-4,2) is reflected over the line x= 3 to create the point A’. What are the coordinates of A
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The coordinate of A would be (10,2)
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A car travels at a speed of 55 kilometers per hour.Find the distance travelled by the car in 12 minutes and 30 seconds.Find the
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Answer:

Step-by-step explanation:

(distance) d = (speed) s * t (time)

                    = 55km/h * 12.30m/s

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                    = 11.275 * 1000

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2 years ago
FIRST PERSON TO ANSWER THIS CORRECTLY GETS BRAINLEIST
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Nine less than twice a number 2x-9

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5 0
3 years ago
Read 2 more answers
What is 56/18 in simplest form
Triss [41]

Answer:

The answer in the simplest form would be 28/9 or 3 1/9

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6 0
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12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests
Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that p = 0.12.

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so n = 18

This probability is:

P = P(X = 0) + P(X = 1)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002

P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458

So

P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460

There is a 34.60% probability that 0 or 1 of them is nearsighted.

5 0
3 years ago
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