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mr_godi [17]
3 years ago
6

Write a real-world example for -0.2 < -0.1 Please help!

Mathematics
2 answers:
Colt1911 [192]3 years ago
8 0

Answer:

Money

Step-by-step explanation:

This is really dumb, but a person can be in debt by 20 cents and another person by 10 cent; therefore, the person who is in debt by 10 cent obviously has to pay less than the person with the 20-cent in debt. Given these facts, the person in debt with one cent has more money then the person in debt with 20 cents.

Len [333]3 years ago
7 0

Answer:

money

Step-by-step explanation:

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0.000000000093 in scientific notation
Inga [223]

no because like he said you have to move the decimal places



6 0
3 years ago
Yoshi's garden three fourths of the flowers are tulips of the two thirds are yellow what fraction of the flowers in Yosi's garde
Alex_Xolod [135]
So if yosh has a garden with 3/4 of the flowers are tulips and 2/3 are yellow if you subtract 3/4 from 2/3 then you will get the awnser that you are looking for. Which is 1/12.
6 0
4 years ago
A drama class has a total of 39 students. The number of males is 9 more than the number of females. How many males and how many
Artist 52 [7]

Answer:

Step-by-step explanation:M+F=39

M+F=39

F=M-9

Substitute

M + M - 9 = 39

2M = 48

M=48/2

M=24

24+F=39

F=39-24=15

F=15, M=24

3 0
3 years ago
Read 2 more answers
Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/3?
Marizza181 [45]
The first one! y+2=(x+3)
5 0
4 years ago
Renee scores an average of 153 points in a game of bowling, and her points in a game of bowling are normally distributed. Suppos
Lelu [443]

Answer:

\sigma=\frac{175-153}{2}=11

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent points in a game of bowling of a population, and for this case we know the distribution for X is given by:

X \sim N(153,unknown)  

Where \mu=153 and \sigma=?

We know that the value for Renee is X=175 and the z score obteined was Z=2.

Solution to the problem

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{X-\mu}{\sigma}

We are interested on the value of \sigma and we can solv for it:

z \sigma = X-\mu

\sigma=\frac{X-\mu}{z}

And replacing the values we have:

\sigma=\frac{175-153}{2}=11

 

5 0
3 years ago
Read 2 more answers
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