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2 years ago

1) When the plumber comes to my house to fix the leaky faucet, he charges a flat rate of

2 answers:

8 0

EXPLANATION:
Money charging per hour = $22
Additional charge= $50
Final bill= $116
Final bill removing the additional charge= $(116 - 50) = $66
Time the plumber was in the house= (66/22)hr = 3hr.

ANSWER: The plumber was there for 3 hours.

Hope it helps u!

Travka [436]2 years ago

4 0

Answer:

3 hours

Step-by-step explanation:

To find the number of hours the plumber was at the house, we need to solve for x.

22x + 50 = 116

22x = 116 - 50

22x = 66

22x/22 = 66/22

x = 3

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Digiron [165]

The answer is g. 47.1

you use the formula
c= π d
then plug is 15 for d and you should get the answer

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2 years ago

The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th

zimovet [89]

Answer:

CLASS FREQUENCIES RELATIVE FREQUENCIES

A 60 0.5

B 12 0.1

C 48 0.4

TOTAL 120 1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS FREQUENCIES RELATIVE FREQUENCIES

A 60 0.5

B 12 0.1

C 48 0.4

TOTAL 120 1

5 0

2 years ago

5x6 = (_X 6) + (2x_)

kati45 [8]

Answer:

(3 x 6) + (2 x 6)

Step-by-step explanation:

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2 years ago

the combined age of april and laura is 23 years. laura's age is two years more than half of april's age. what is laura's age

Kipish [7]

Laura's age is 9 years.

Solution:

Let x be the age of April.

Laura's age = 2 years more than half of April's age

Convert statement into algebraic expression:

Half of April's age = $\frac{x}{2}$

2 years more than half of April's age = $\frac{x}{2}+2$

Combined age of April and Laura = 23

⇒ April's age + Laura's age = 23

$$\Rightarrow \ \ x+(\frac{x}{2}+2) =23$

$$\Rightarrow \ \ x+\frac{x}{2}+2 =23$

$$\Rightarrow \ \ \frac{x}{1}+\frac{x}{2}+\frac{2}{1} =23$

To add the fractions make the denominators same.

Multiplying 2 on both numerator and denominator of unlike terms, we get

$$\Rightarrow \ \ \frac{x\times2}{1\times2}+\frac{x}{2}+\frac{2\times2}{1\times2} =23$

$$\Rightarrow \ \ \frac{2x}{2}+\frac{x}{2}+\frac{4}{2} =23$

Denominators are same, now add the fractions.

$$\Rightarrow \ \ \frac{2x+x+4}{2} =23$

Do cross multiplication.

$$\Rightarrow \ \ 2x+x+4=23\times2$

$$\Rightarrow \ \ 3x=46-4$

$$\Rightarrow \ \ 3x=42$

$$\Rightarrow \ \ x=14$

Aprils's age = 14 years

Laura's age = $\frac{14}{2}+2$

= 7 + 2

Laura's age = 9

Hence Laura's age is 9 years.

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