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Lelechka [254]
3 years ago
10

Please help on 8 thank youuuuuuuuuu

Chemistry
1 answer:
enyata [817]3 years ago
6 0

Answer:

b)5l x 10kg  c)10kg + 9l   (Not sure for the last 1)

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A eudiometer contains a 65.0 ml sample of a gas collected
SCORPION-xisa [38]

Answer:

53.1 mL

Explanation:

Let's assume an ideal gas, and at the Standard Temperature and Pressure are equal to 273 K and 101.325 kPa.

For the ideal gas law:

P1*V1/T1 = P2*V2/T2

Where P is the pressure, V is the volume, T is temperature, 1 is the initial state and 2 the final state.

At the eudiometer, there is a mixture between the gas and the water vapor, thus, the total pressure is the sum of the partial pressure of the components. The pressure of the gas is:

P1 = 92.5 - 2.8 = 89.7 kPa

T1 = 23°C + 273 = 296 K

89.7*65/296 = 101.325*V2/273

101.325V2 = 5377.45

V2 = 53.1 mL

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4 years ago
What is physical weathering NOT caused by? (pls i really need help with this!!)
Anarel [89]

Answer:

the changing tempure in rocks causing it to back apart

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3 years ago
What is the name of this compound
lys-0071 [83]

Answer:

horizontal

Explanation:

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How do sediments form?
Valentin [98]
Sedimentary<span> rocks are formed when </span>sediment<span> is deposited out of air, ice, wind, gravity, or water flows carrying the particles in suspension</span>
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The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles
sergejj [24]

<u>Answer:</u> The expression for equilibrium constant is K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

For the general chemical equation:

aA+bB\rightleftharpoons cC+dD

The expression for K_c is given as:

K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical reaction:

2HgO(s)+H_2O(l)+2Cl_2(g)\rightleftharpoons 2HOCl(aq.)+HgO.HgCl_2(s)

The expression for K_{eq} is given as:

K_{eq}=\frac{[HOCl]^2[HgO.HgCl_2]}{[HgO]^2[H_2O][Cl_2]^2}

The concentration of solid is taken to be 0.

So, the expression for K_{eq} is given as:

K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

3 0
4 years ago
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