<u>Answer:</u>
When Anne pushes the wheelbarrow 25 meters the work done is 1120 joules
<u>Solution:</u>
We know 
Anne is pushing the wheelbarrow with a force of 70 N at an angle of 
with the horizontal
So the force of Anne will be 
She pushes the wheelbarrow 25 meter, So D = 25 meters
So, the 
Anne has done total 1120 joules work.
ANSWER: -57
14+{−2+3[1+3(−6−2)]}
= 14+{−2+3[1+3(-8)]}
= 14+{−2+3[1+(-24)]}
= 14+{−2+3[1-24]}
= 14+{−2+3[-23]}
= 14+{−2+[-69]}
= 14+{−2-69}
= 14+(-71)
= 14 - 71
= -57
Answer:
y = 3/2x + 6
Step-by-step explanation:
2/3 y - 4 = x
2/3y = x + 4
y = 3/2 * (x + 4)
y = 3/2x + 6
Since 
(density = mass/volume), we can get the mass/weight of the liquid by integrating the density 
over the interior of the tank. This is done with the integral
which is more readily computed in cylindrical coordinates as
