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3 years ago

Hi im Elizabeth and im new what do i do

Mathematics

2 answers:

Alecsey [184]3 years ago

5 0

Answer:

Step-by-step explanation:

Gwar [14]3 years ago

3 0

Answer:

You ask and answer questions to get help and help others.

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98 points! please answer this question ASAP!

Leni [432]

I do agree its all even. Mark brainliest if correct.

8 0

3 years ago

Read 2 more answers

OABCD is a pyramid with a rectangular base of sides 15cm by 9cm.Given that the slant height OQ is 16cm find its

crimeas [40]

Hello! Your answer is below... Remember : h = height and v = volume

Answer:

H = 15.35 cm

V = 690.75 m^

Step-by-step explanation:

(H= height, V = volume, ^= square, √ = square root )

1. divide 9/2

=4.5 cm

2. use the pythagorean theorem

H=√16^-4.5^

H=15.35

if your looking for volume

1. use the formula for volume of the pyramid which is:

1/3 x base area x height

base area x height /3

2. then you substitute

1/3 x (9)(15) x 15.35

(9)(15) x 15.35 /3

V= 690.75 m^

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

3 0

3 years ago

Read 2 more answers

What is the value of x?<br><br> x= ___ °

JulsSmile [24]

Answer:

80°

Explanation:

All angles inside a triangle must add up to 180°

6 0

3 years ago

What is [(6.2x8.4) minus 9.28]

igor_vitrenko [27]

The answer is 42.8

I hope that helps<span />

8 0

3 years ago

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Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec

expeople1 [14]

Answer:

$cot x = \frac{cos x}{sin x}$

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

$cos x cot x + sin x$

We know from math properties that the definition for cot is $cot x = \frac{cos x}{sin x}$

If we use this definition we got:

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

Now we can use the following identity:

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

4 0

4 years ago