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timurjin [86]
2 years ago
5

Which of the following represents an electron configuration that corresponds to the valence electrons of an element for which th

ere is an especially large jump between the second and third ionization energies?
A. ns^2
B. ns^2np^1
C. ns^2np^2
D. ns^2np^3
Chemistry
2 answers:
Lelechka [254]2 years ago
7 0

Answer:

C

Explanation:

I'd assume it would be C because the two electrons present in the l = 2 subshell (p) are degenerate. As a result the energy needed to remove an electron in a lower subshell (l=1) would be substantially different compared to the other subshell.

Mademuasel [1]2 years ago
6 0

The electron configuration that corresponds to the valence electrons of an element for which there is an especially large jump between the second and third ionization energies is ns^2.

The valence electron configuration of an atom refers to the arrangement of electrons on the outermost shell of the atom.

Recall that a large jump in ionization energy occurs when electrons are removed from inner shells of the atom.

If we study our options closely, we will discover that option A has only two electrons in the valence shell (ns^2).

This means that the third ionization energy involves removing electrons from an inner shell which leads to large jump.

Learn more: brainly.com/question/14283892

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Write the overall reaction for cellular respiration
goblinko [34]
C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O
7 0
3 years ago
A compound containing chromium, Cr; chlorine, Cl; and oxygen, O, is analyzed and found to be 33.6% chromium, 45.8% chlorine, and
Assoli18 [71]

Answer

The empirical formula is CrO₂Cl₂

Explanation:

Empirical formula is the simplest whole number ratio of an atom present in a compound.

The compound contain, Chromium=33.6%

                                         Chlorine=45.8%

                                          Oxygen=20.6%

And the molar mass of Chromium(Cr)=51.996 g mol.

                 Chlorine containing molar mass (Cl)= 35.45    g mol.

                 Oxygen containing molar mass (O)=15.999  g mol.

Step-1

 Then,we will get,

Cr=\frac{1}{51.996} \times33.6=0.64 mol

Cl= \frac{1}{35.45} \times45.8=1.29 mol.

O=\frac{1}{15.99} \times=1.28 mol.

Step-2

Divide the mole value with the smallest number of mole, we will get,

Cr= \frac{0.64}{0.64} =1

Cl= \frac{1.29}{0.64} =2

O= \frac{1.28}{0.64} =2

Then, the empirical formula of the compound is CrO₂Cl₂ (Chromyl chloride)

4 0
3 years ago
Read 2 more answers
Which of the following is true for the equilibrium constant of a reaction? (5 pc
Slav-nsk [51]

The equilibrium constant of the reaction is represented by the symbol K. Thus, option C is the correct and accurate statement about the equilibrium constant.

<h3>What is the equilibrium constant?</h3>

The equilibrium constant is a representation of the concentration of the products and the reactants of the reaction that is raised to the powers through their stoichiometry coefficient.

Its value varies and changes at different temperatures and is not always less than 1. The equilibrium constant is the ratio of the coefficient of the products to reactants.

Therefore, option C. equilibrium constant is represented by K is true.

Learn more about the equilibrium constant here:

brainly.com/question/12429748

#SPJ1

8 0
2 years ago
Calculate the hydroxide ion consentration of a solution with pH = 3.25. show all calculations leading to your answer.
lidiya [134]
First you calculate the pOH of the solution:

pH+ pOH = 14

3.25 + pOH = 14

pOH = 14 - 3.25

pOH = 10.75

<span>Concentration of [OH]</span>⁻<span> in solution:
</span>
[ OH⁻ ] = 10 ^{-pOH}

[ OH⁻ ]  = 10^ - 10.75

[OH⁻] = 1.778 x 10⁻¹¹ M

hope this helps !


6 0
2 years ago
How many grams of Chromium can be formed when 150 grams of
valentinak56 [21]

Answer: 104 g

Explanation: reaction Cr2O3 + 3 H2 ⇒ 2 Cr + 3 H2O

M(Cr2O3) = 150 g/mol, so n = m/M = 1.0 mol

Number of moles of H2 should be 3.0 moles and

It is much greater (150 g / 2.016 g/mol)

1 mol Cr2O3 produces 2 mol Cr.

Mass m= 2.0 mol· 52g/mol= 104 g

6 0
2 years ago
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