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Marina CMI [18]
3 years ago
10

Calculate the percent dissociation of trimethylacetic acid in a aqueous solution of the stuff. You may find some useful data in

the ALEKS Data resource. Round your answer to significant digits.

Chemistry
1 answer:
LuckyWell [14K]3 years ago
3 0

Answer:

percentage dissociation of trimethylacetic acid in a 0.57M  aqueous solution = 0.40%

Explanation:

check attachment below for more information o the answer.

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A student carried out an acid-base titration by adding NaOH solution from a buret to an Erlenmeyer flask containing HCl solution
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Answer:

Shift in equilibrium position

Explanation:

The reddish-pink colour signalled the equivalence point. That is, pH=PKind. This was the point at which we have commonly the called the end point of the titration which has been carried out. As the solution was left to stand after this equivalence point was attained, the equilibrium position shifted again towards the acid side and the solution turned colourless once more. The equilibrium position indicated by the colour change depends on the H+ concentration of the solution.

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Calculate the molality of 2.0 M MgCl2 solution. The density of the solution is 1.127 g/mL. (The molar mass of MgCl2 = 95.211 g/m
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The answer is 2.135 mol/Kg

Given that molarity is 2M, that is, 2 moles in 1 liter of solution.

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Volume of solution is 1L or 1000 ml

mass of solution (m) = density × volume

m₁ = density × volume = 1.127 × 1000 = 1127 g

mass of solute, m₂ = number of moles × molar mass

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m₂ = 190.422 g

mass of solvent = m₁ - m₂

= 1127 - 190.422

= 936.578 g

= 0.9366 Kg

molality = number of moles of solute / mass of solvent (in kg)

= 2 / 0.9366

= 2.135 mol/Kg

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Explanation:

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