M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,
timama [110]
Answer:
Step-by-step explanation:
Given
<LON = 77°
<LOM = (9x+44)°
<MON = (6x+3)°
The addition postulate is true for the given angles since tey have a common point O:
<LON = <LOM+<MON
Since we are not told what to find we can as well look for the value of x, <LOM and <MON
Substitute the given parameters and get x
77 = 9x+44+6x+3
77 = 15x+47
77-47 = 15x
30 = 15x
x = 30/15
x = 2
Get <LOM:
<LOM = 9x+44
<LOM = 9(2)+44
<LOM = 18+44
<LOM = 62°
Get <MON:
<MON = 6x+3
<MON = 6(2)+3
<MON = 12+3
<MON = 15°
Answer:218 degrees
Step-by-step explanation:c
<u>Given</u>:
Given that the triangle ABC is similar to triangle FGH.
We need to determine the value of x.
<u>Value of x:</u>
Since, the triangles are similar, then their sides are proportional.
Thus, we have;
Let us consider the proportion 
to determine the value of x.
Substituting AB = 9 cm, GF = 13.5 cm, BC = 15 cm and GH = x, we get;
Cross multiplying, we get;
Thus, the value of x is 22.5 cm
Hence, Option F is the correct answer.
Answer:
-10x + y = 63
Step-by-step explanation:
Let's find the slope of this line. Going from (-7, -7) to (-6, 3), the "run" is +1 (this is the increase in x) and the "rise" is -10 (y increases by 10). Thus, the slope, m, is m = rise / run = 10 / 1 = 10.
Using the point-slope version of the equation of a straight line, we get
y + 7 = 10(x + 7)
Performing the multiplication results in
y + 7 = 10x + 70.
Rearranging these terms in the form Ax + By = C, we get:
-10x + y = 63
Check this by substituting -6 for x and 3 for y:
-10(-6) + 3 = 63 This is TRUE
