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3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Chemistry

1 answer:

Lera25 [3.4K]3 years ago

6 0

number one the top three are (Mars Wrigley Confectionery, Ferrero Group, Mondelez International.)

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What compound has the ability to absorb large amounts of heat without itself increasing dramatically in temperature

Scorpion4ik [409]

It can be anything with a big heat capacity like water

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3 years ago

What is the resulting formula unit when aluminum (Al) and phosphorus (P) bond?

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<span>aluminium phosphide AlP</span>

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3 years ago

Making solutions is an extremely important component to real-life chemistry. If you make 3.00 L of a solution using 90.0 g of so

kumpel [21]

Answer:

Final concentration of NaOH = 0.75 M

Explanation:

For $NaOH$ :-

Given mass = 90.0 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{90.0\ g}{39.997\ g/mol}$

$Moles\ of\ NaOH= 2.2502\ mol$

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Where, Volume must be in Liter.

It is denoted by M.

Given, Volume = 3.00 L

So,

$Molarity=\frac{2.2502\ mol}{3.00\ L}=0.75\ M$

<u>Final concentration of NaOH = 0.75 M</u>

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4 years ago

For the decomposition of calcium carbonate, consider the following thermodynamic data (Due to variations in thermodynamic values

In-s [12.5K]

Answer : The temperature in kelvins is, $T>1108.695K$

Explanation : Given,

$\Delta H$ = 178.5 KJ/mole = 178500 J/mole

$\Delta S$ = 161.0 J/mole.K

Gibbs–Helmholtz equation is :

$\Delta G=\Delta H-T\Delta S$

As per question the reaction is spontaneous that means the value of $\Delta G$ is negative or we can say that the value of $\Delta G$ is less than zero.