It has 4 pcs of Carbon (C) and 8 pcs of Hydrogen (H) so the formula is C4H8 - calls Butene.
Hope it helps!
#MissionExam001
Sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags since the require more mass and produce less gas.
<h3>Which is the better chemical for an airbag?</h3>
The chemical equation for the production of nitrogen gas from sodium azide is given below:
1 mole or 66 go of sodium azide produces 3 moles or 67.2 L of nitrogen gas.
The equation for the production of carbon dioxide from sodium bicarbonate and acetic acid is given below:
- Na₂CO₃ + CH₃COOH → CH₃COONa + CO₂ + H₂O
1 mole, 106 g of Na₂CO₃ and 1 mole, 82 g of CH₃COOH are required to produce 1 mole or 22.4 L of CO₂.
The mass of sodium azide required is less than that of sodium bicarbonate and acetic acid required. Also, sodium azide produces a greater volume of gas. Therefore, sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags.
In conclusion, sodium azide is a better choice in airbags.
Learn more about airbags at: brainly.com/question/14954949
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Answer:
B. Boiling Point
Explanation:
To separate salt from water, you need to boil it until all the water evaporates, and you will be left with salt.
C. The neutron number.
An element is determined based on how many protons has, if the protons number change then you got a new element.
If the number of neuron change you got the same element except it will be a bit heavier or lighter if you are gaining or loosing neutrons. Those variations of an element are called the isotops of the element.
The protons and neutrons toghether form the nucleus of the atom that is heavy and dense as an elephant.
The electrons are light as fleas and stay on the shels of around the nucleus and if they are more then the number of protons they make the atom negatively charged and vice versa.
The temperature that the balloon will expand to 3.50 l is 463.56 K
<em><u> calculation</u></em>
by use of Charles law formula
that is V1/T1 = V2/T2 where;
V1 = 2.25 l
T1= 298 k
V2= 3.50 l
T2=?
make T2 the subject of the formula T2 =(V2 xT1) /v1
T2= (3.50 l x 298 K) /2.25 L = 463.56 K
