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Free_Kalibri [48]
3 years ago
6

At 0.96 liters how much to fill a 15 gallon tank

Chemistry
1 answer:
Nat2105 [25]3 years ago
3 0
Ummmmmmmm...... Idk sorry
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Compounds can be made by combining ________
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hfew hv ihrv i

Explanation:

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Name the element which has twice the number of electrons in its second shell as in the first shell write it's electronic configu
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3 years ago
What is the pH of .0003 M of NaOH
s344n2d4d5 [400]

We are given that the concentration of NaOH is 0.0003 M and are asked to calculate the pH

We know that NaOH dissociates by the following reaction:

NaOH → Na⁺ + OH⁻

Which means that one mole of NaOH produces one mole of OH⁻ ion, which is what we care about since the pH is affected only by the concentration of H⁺ and OH⁻ ions

Now that we know that one mole of NaOH produces one mole of OH⁻, 0.0003M NaOH will produce 0.0003M OH⁻

Concentration of OH⁻ (also written as [OH⁻]) = 3 * 10⁻⁴

<u>pOH of the solution:</u>

pOH = -log[OH⁻] = -log(3 * 10⁻⁴)

pOH = -0.477 + 4

pOH = 3.523

<u>pH of the solution:</u>

We know that the sum of pH and pOH of a solution is 14

pH + pOH = 14

pH + 3.523 = 14                              [subtracting 3.523 from both sides]

pH = 10.477                        

8 0
3 years ago
3/4(x-2)=x-1 please answer me ​
Elan Coil [88]

Answer:

-2

Explanation:

3/2 (x-2) = x-1

<=> 3/4 x - 3/2 = x-1

<=> 3/4 x - x = 3/2 -1

<=> -1/4 x =1/2

<=> x= -2

3 0
3 years ago
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How many calories is required to change the temperature of 2.18g of water from 15.3°C to 69.5°C. The specific heat of liquid wat
lozanna [386]

The number  of calories that are  required  to change the temperature  of 2.18 g of water from 15.3 c to 69.5 c is  <u>118.16 cal</u>


    <u><em> calculation</em></u>

  •    Heat in calories  = MCΔ T where,
  • M(mass)= 2.18 g
  • C(specific heat capacity)= 1.00 cal/g/c
  • ΔT( change in temperature)= 69.5- 15.3 =54.2 c

 heat is therefore= 2.18 g x 1.00 cal/g/c  x 54.2 c=118.16  cal

7 0
3 years ago
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