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Lorico [155]
3 years ago
12

Write the equation of the parabola in vertex form. vertex (2,1), point (3,- 1) f(x) =

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0

Answer:

f(x) = -2(x - 2)^2 + 1

Step-by-step explanation:

Given the vertex, (2, 1) and point (3, -1):

We can plug in those values into the Vertex Form:

f(x) = a(x - h)^2 + k

f(x) = a(x - 2)^2 + 1

Plug in the other point, (3, -1) into the equation to solve for <em>a</em>:

-1 = a(3 - 2)^2 + 1

-1 = a(1)^2 + 1

-1 = <em>a</em>1 + 1

Subtract 1 from both sides of the equation to solve for a:

-1 - 1 = 1<em>a </em>+ 1 - 1

-2 = 1a

\frac{-2}{1} = \frac{1a}{1}

-2 = a

Therefore, the equation of the parabola in Vertex Form is:

f(x) = -2(x - 2)^2 + 1

where a = -2, and the vertex, (2, 1) as its maximum point.

lorasvet [3.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

Vertex form of parabola = a(x - h)^2 + k

                                          =  (3 - 2)^2 + 1

                                           = 1 + 1 = 2

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Answer:

1 is the 3rd option

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3 0
4 years ago
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6 1/2+n=12. please explain for me I dunno how to do this.
Temka [501]
Hey there!

Let's first define our goal. Our goal here is to be able to isolate the variable, n, and solve for it by moving everything to the other side. We see that we have two sides of the equation, and by using the property of equality which states that whatever you do to one side you do to the other and the expression remains equal, we can solve this equation.

It looks like the only thing we have on the left side with n is that 6 1/2. In order to get rid of it, we must subtract it from both sides, because the property of equality states you must do the inverse operation.

We have:

n = 12 - 6 1/2

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Hope this helps!
7 0
3 years ago
Solve the following quadratic equation. <br> d²-5d+6=0
natima [27]

Answer:

d=2 and d=3

Step-by-step explanation:

d^2-5d+6=0

(d-2)(d-3)=0

d=2 and d=3

3 0
3 years ago
Read 2 more answers
Let an be the sum of the first n positive odd integers.
sesenic [268]

Answer:

A) The first 4 terms of the sequences are: a_{1} =16, a_{2} =24, a_{3} =32 and a_{4} =40.

B) An explicit formula for this sequence can be written as: a_{n} =8*(n+1)

C) A recursive formula for this sequence can be written as:

\left \{ {{a_{1} =16} \atop {a_{n} =a_{n-1}+8}} \right.

Step-by-step explanation:

A) You can find the firs terms of this sequence simply selecting an odd integer and summing the consecutive 3 ones:

a_{n} = Odd_{n}+Odd_{n+1}+Odd_{n+2}+Odd_{n+3} (a.1)

a_{1}=1+3+5+7=16

a_{2}=3+5+7+9=24

a_{3}=5+7+9+11=32

a_{4}=7+9+11+13=40

B) Observe the sequence of odd numbers 1, 3, 5, 7, 9, 11, 13(...).

You can express this sequence as:

Odd_{n}=(2*n-1) (b.1)

If you merge the expression b.1 in a.1, you obtain the explicit formula of the sequence:

a_{n} = Odd_{n}+Odd_{n+1}+Odd_{n+2}+Odd_{n+3} (a.1)

a_{n} = (2*n-1)+((2*(n+1)-1))+((2*(n+2)-1))+((2*(n+3)-1)) (b.2)

a_{n} = 8*n+8 (b.3)

a_{n} =8*(n+1) (b.s)

C) The recursive formula has to be written considering an initial term and an N term linked with the previous term. You can see an addition of 8 between a term and the next one. So you can express each term as an addition of 8 with the previous one. Therefore, if the first term is 16:

\left \{ {{a_{1} =16} \atop {a_{n} =a_{n-1}+8}} \right. (c.s)

5 0
3 years ago
What is x in this problem? someone please help
Vedmedyk [2.9K]
X=21
This is because both of those angles are equal, so you would divide 42 by 2 and get 21
7 0
3 years ago
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