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Bond [772]
3 years ago
7

Solve the following system of equations.

Mathematics
1 answer:
Yuri [45]3 years ago
7 0

Answer:

x= 12

y= 10

best of luck mate

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I need help pls <br><br> I WILL GIVE BRAINLIEST <br> Pls help
uranmaximum [27]

Answer:

1. The square root of 100

2.c=27.11

d=13.96

e=12.6

<u>Step</u><u> </u><u>by</u><u> </u><u>step</u><u> </u><u>explanation</u><u>:</u><u> </u>

1. 2×50=100 the geometric mean is the square root of 100

2. The diagram is made up of three right angled triangles the big outer one and two triangles inside the big one thus we can use the pythagorean theorem to come up with expressions which will help us in solving the unknown parts as below.

c²=30²-d²

c²=e²+24²

d²=e²+6²

both the following add up to c² meaning they are equal:

c²=30²-d²

c²=e²+24²

thus

30²-d²=e²+24²

I want to remain with d² only thus;

30²-24²-e²=d²

900-576=324 (squareroot of 324=18) so

d²=18²-e² and d²=e²+6²

both the above add up to d² meaning they are equal thus;

18²-e²=e²+6²

18²-6²=e²+e²

324-36=2e²

318=2e²

159=e²

e=12.61

<em>Thus</em><em> </em><em>d</em><em>²</em><em>=</em><em>e</em><em>²</em><em>+</em><em>6</em><em>²</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>²</em><em>=</em><em>1</em><em>2</em><em>.</em><em>6</em><em>1</em><em>²</em><em>+</em><em>6</em><em>²</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>²</em><em>=</em><em>1</em><em>5</em><em>9</em><em>+</em><em>3</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>²</em><em>=</em><em>1</em><em>9</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>=</em><em>1</em><em>3</em><em>.</em><em>9</em><em>6</em>

<em>c</em><em>²</em><em>=</em><em>e</em><em>²</em><em>+</em><em>2</em><em>4</em><em>²</em>

<em>c</em><em>²</em><em>=</em><em>12.61</em><em>²</em><em>+</em><em>2</em><em>4</em><em>²</em>

<em>c</em><em>²</em><em>=</em><em>1</em><em>5</em><em>9</em><em>+</em><em>5</em><em>7</em><em>6</em>

<em>c</em><em>²</em><em>=</em><em>7</em><em>3</em><em>5</em>

<em>c</em><em>=</em><em>27.11</em>

<em> </em>

<em>I</em><em> </em><em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

3 0
3 years ago
Solve: XC - XV. Show your answer as a Roman Numeral. Standard Roman Number Numeral 1 1 5 V 10 Х 50 L 100 С C 500 D 1,000 M OA) V
Keith_Richards [23]

Answer:

5,6,7

Step-by-step explanation:

SEE THE IMAGE FOR SOLUTION

HOPE IT HELPS

HAVE A GREAT DAY

6 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! <br><br> What is (f/g)(x) ?
Rudiy27

Answer:   \bold{D.\ \dfrac{x+4}{x}\ where\ x \neq 0, \dfrac{2}{3}}

<u>Step-by-step explanation:</u>

f(x) = 3x² + 10x - 8

g(x) = 3x² - 2x


\dfrac{f(x)}{g(x)}=\dfrac{3x^2+10x-8}{3x^2-2x}=\dfrac{(3x-2)(x+4)}{x(3x-2)}=\dfrac{x+4}{x}

Restriction on x: the denominator cannot be equal to zero. So,

    x(3x - 2) ≠ 0  

→  x ≠ 0     and     3x - 2 ≠ 0

                             3x       ≠ 2

                               x       \neq \dfrac{2}{3}


8 0
3 years ago
F(x) = 3x - 3 <br> g(x) = 4x+5 <br> find (f•g) (3) <br><br> only numerical answers work
Andreas93 [3]

Answer:

48 bcoz u do 4(3)+5 do f(g) than for f(17) u do 3(17)-3

6 0
3 years ago
Complete the square to re-write the quadratic function in vertex form: y=x2-x+3
Anna [14]

Answer:

Step-by-step explanation:

hello :

note : the vertex form is :

ax²+bx+c = a(x+(b)/(2a))²-  delta/4a²   and   delta = b²- 4ac

in this exercice you have : a =1    b = -1   and  c= 3

continu ..........

5 0
2 years ago
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