The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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Answer:
2, 12
Step-by-step explanation:
LCM = Least common multiple
LCM of 2 and 12 is 12
2 4 6 8 10 12
12
LCM of 6 and 8 is 24
6 12 18 24
8 16 24
LCM of 3 and 8 is 24
3 6 9 12 15 18 21 24
24
LCM of 12 and 24 is 24
12 24
24
To find the answer, we multiply 1,047.30 by 6.2% which is 0.062 in percentage.
1047.30 x 0.062 = 64.93
64.93 is being taken away.
Answer:
8 seed packets
Step-by-step explanation:
you just need to have half the amount of seed packets of the number of tomato plants grown
Answer:
I think its B
Step-by-step explanation:
Hope this helps:)
