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noname [10]
3 years ago
5

How do I solve the problem 7(2m+6) + 8m

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
4 0
It is: you use distribution method to solve the problem.
14m + 42 + 56m
Then you combine like terms:
14m + 56m + 42
Then you add
70m + 42 is your answer
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45 points!<br><br> x+1(8+5)+y2-3(x3+y-4)=36-4+x7-y-1<br> pls i need help now!
Nadya [2.5K]
The answer is X=-2/5
3 0
2 years ago
What is the value of x?<br> *36<br> *72<br> *108<br> *144
Anit [1.1K]

Answer:

72

Step-by-step explanation:

6 0
2 years ago
Which of the following transformations are used when transforming the graph of the parent function...
hram777 [196]

1. 1st transformation is translation the parent function y=\log_5x 6 units to the right to get the function y=\log_5(x-6).

2. 2nd transformation is reflection the function y=\log_5(x-6) over the x-axis. This transformation gives you the function y=-\log_5(x-6).

3. 3rd transformation is vertical stretch of the function y=-\log_5(x-6) by a factor of 2 to get the function y=-2\log_5(x-6).

Only last two are present in options, then

answer: C and D.

5 0
3 years ago
What is the simplified expression for,
Nostrana [21]

Here are a few rules you need to know for this equation:

  • Multiplying exponents of the same base: x^m\times x^n=x^{m+n}
  • Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}
  • Turning a negative exponent to a positive one: x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m

So this is our algebraic expression: \frac{3^{-4}\times 2^3\times 3^2}{2^4\times 3^{-3}}

Firstly, multiply 3^-4 and 3^2: \frac{3^{-4+2}\times 2^3}{2^4\times 3^{-3}}=\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}

Next, divide:

\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}=3^{-2-(-3)}2^{3-4}=3^12^{-1}

Next, turn the negative exponent into a positive one: 3^12^{-1}= \frac{3}{2}

<u>Your final answer is 3/2, or 1.5.</u>

6 0
3 years ago
I need help please please please
Ira Lisetskai [31]

Answer:

y=5,5 1/3

Step-by-step explanation:

hope this helps

5 0
2 years ago
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