99 ÷ 3 = 33 so each box weighs 33lbs or pounds each
so 33 × 4 = 132 pounds
or
99 + 33 = 132 pounds
Answer:
The amount of Soyabean = 608.82 pounds.
The amount of Oats = 900-608.82 = 291.18 pounds.
Step-by-step explanation:
Given that the Soybean Meal has 46% CP and Oats has 12% CP.
The total amount of ration is 900 lbs of 35% CP.
Let x pounds of Soyabean has been used, so,
the amount of Oats = 900-x lbs.
The CP amount in 900 lbs mixture will be equal to the sum of CP amounts in x lbs Soyabean and 900-x lbs Oats, i.e
35% of 900 = 46% of x + 12% of (900-x)




lbs.
So, the amount of Soyabean = 608.82 pounds.
The amount of Oats = 900-608.82 = 291.18 pounds.
Answer:
9. n=-15 , 10. f=6, sorry i can't help you more I am just tired and have to get some rest but i hope this helps
Step-by-step explanation:
9. Eight less than 1/3 a number n is -13
so -13 = 1/3n -8
then
-5 = 1/3n
multiply 3 to each side
-15 = n
10. a number f multiplied by -12.3 is -73.8
so -12.3f= -73.8
divide -12.3 on each side
so f=6
First find the slope:
m = ( 2 - 1 ) / ( 0 - (-1) ) = 1 / 1 = 1
Set up slope-intercept form:
y = 1·x +2
Now move x and y to the left and leave 2 on the right:
-x + y = 2
This is also equivalent to x - y = -2, so that just depends if you want your x coefficient to be positive or negative.
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.