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iragen [17]
3 years ago
14

1) Escribe las funciones trigonométricas pedidas dados los siguientes triángulos rectángulos.

Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0
It’s horizontal so it would be yes
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Divide the following quantiles in the given ratio £100 1:3 £80 3:5 £250 2:3:5
goblinko [34]

Answer:

Step-by-step explanation:

a.

£100

1:3

1+3=4

1/4×£100

=£25

3/4×£100

=£75

b.

£80

3:5

3+5=8

3/8×£80

=£30

5/8×£80

=£50

C.

£250

2:3:5

2+3+5=10

2/10×£250

=£50

3/10×£250

=£75

5/10×£250

=£125

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3 years ago
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Anni [7]
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Answer:

landslide

Step-by-step explanation:

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1)Alexpleyadefn
Anarel [89]

Answer:

Step-by-step explanation:

answer to the question:

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(\tan ^(2)\theta \cos ^(2)\theta -1)/(1+\cos (2\theta ))=
Vitek1552 [10]

(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

Recall that

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

so cos²(<em>θ</em>) cancels with the cos²(<em>θ</em>) in the tan²(<em>θ</em>) term:

(sin²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

Recall the double angle identity for cosine,

cos(2<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

so the 1 in the denominator also vanishes:

(sin²(<em>θ</em>) - 1) / (2 cos²(<em>θ</em>))

Recall the Pythagorean identity,

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

which means

sin²(<em>θ</em>) - 1 = -cos²(<em>θ</em>):

-cos²(<em>θ</em>) / (2 cos²(<em>θ</em>))

Cancel the cos²(<em>θ</em>) terms to end up with

(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>)) = -1/2

7 0
3 years ago
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