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77julia77 [94]
3 years ago
15

Matt is mailing a rectangular package at the post office the box's volume is 24 in.³ what are all of the possible dimensions len

gth width and height that a package could be
Mathematics
1 answer:
mars1129 [50]3 years ago
7 0

Answer:

The answer to your question is below

Step-by-step explanation:

Data

Volume = 24 in³

Process

1.- Find the prime factors of 24

                        24  2

                         12  2

                          6  2

                          3  3

                           1

2.- Volume of a rectangular package

             Volume = length x height x width

3.- Possible values are, combine the prime factors to find the volume

             Volume = 4 x 2 x 3   or

             Volume = 2 x 4 x 3

             Volume = 3 x 2 x 4

             Volume = 2 x 2 x 6

             Volume = 6 x 2 x 2

             Volume = 2 x 6 x 2

             Volume = 12 x 2 x 1

             Volume = 1 x 12 x 2

             Volume = 2 x 1 x 12

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Answer:

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Step-by-step explanation:

Step 1: We have a ratio of 1 cup of walnuts to 1 cup of walnut muffins

1:1

Step 2: We are given 3 batches of walnut muffins

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Step 3: We know this is a 1 to 1 ratio

3:3

Therefore you will need 3 cups of walnuts to make 3 batches of muffins

4 0
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A scientist had 3/4 of a bottle of a solution. She used 1/6 of the solution in an experiment. How much of the bottle did she use
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3 0
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A treasure chest sinks at a rate no less than 20 ft per second. The floor of the ocean is at most at -4200 feet. Will the treasu
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3 years ago
If two angles of one triangle equal in measure to two angles of another triangle then the third angles of the triangle
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Answer:

Are also equal

Step-by-step explanation:

Say triangle A has the angles 30 and 60. triangle b also has those angles. Total angle of any triangle is 180 so 180-60-30 = 90 for triangle A and it is also the same for triangle b. Thus 90 = 90 angles are the same.

8 0
2 years ago
The following data lists the ages of a random selection of actresses when they won an award in the category of Best​ Actress, al
Valentin [98]

Answer:

a) p_v =P(t_{(9)}

The p value is higher than the significance level given 0.01, so then we can conclude that we FAIL to reject the null hypothesis. And we can say that the true difference for Best Actresses is not significantly lower than the mean for Best​ Actors at 1% of significance.

b) The 99% confidence interval would be given by (-21.469;2.069)

c) We got the same conclusion as part a, sicne the confidence interval contains the value 0, we FAIL to reject the null hypothesis that the difference between the two

Step-by-step explanation:

Part a

Let put some notation  

x=actor's age , y = actress's age

x: 58 41 36 36 34 33 48 37 37 43

y: 26 27 34 26 35 29 23 42 30 34

The system of hypothesis for this case are:

Null hypothesis: \mu_y- \mu_x \geq 0

Alternative hypothesis: \mu_y -\mu_x

The first step is calculate the difference d_i=y_i-x_i and we obtain this:

d: -32, -14, -2, -10, 1, -4, -25, 5, -7, -9

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= -9.7

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =11.451

The 4 step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-9.7 -0}{\frac{11.451}{\sqrt{10}}}=-2.679

The next step is calculate the degrees of freedom given by:

df=n-1=10-1=9

Now we can calculate the p value, since we have a left tailed test the p value is given by:

p_v =P(t_{(9)}

The p value is higher than the significance level given 0.01, so then we can conclude that we FAIL to reject the null hypothesis. And we can say that the true difference for Best Actresses is not significantly lower than the mean for Best​ Actors at 1% of significance.

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The confidence interval for the mean is given by the following formula:  

\bar d \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,9)".And we see that t_{\alpha/2}=3.25  

Now we have everything in order to replace into formula (1):  

-9.7-3.25\frac{11.451}{\sqrt{10}}=-21.469  

-9.7+3.25\frac{11.451}{\sqrt{10}}=2.069  

So on this case the 99% confidence interval would be given by (-21.469;2.069)

Part c

We got the same conclusion as part a, sicne the confidence interval contains the value 0, we FAIL to reject the null hypothesis that the difference between the two means is 0.

8 0
3 years ago
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