Find h (3) if h (t) = 5 (t-1) + 2
1 answer:
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Answer:
Area of Trapezoid is 39 unit²
Step-by-step explanation:
Given as :
For A Trapezoid
The measure of base side 1 = = 10 unit
The measure of base side 2 = = 16 unit
The height of the Trapezoid = h = 3 unit
Let The Area of Trapezoid = A square unit
<u>Now, From Formula</u>
Area of Trapezoid = × (sum of opposite base) × height
I.e A = × (
+
) × h
Or, A = × (10 unit + 16 unit) × 3 unit
Or, A = × (26 unit) × 3 unit
Or, A = × 78 unit²
Or, A = unit²
I.e A = 39 unit²
So, The Area of Trapezoid = A = 39 unit²
Hence, The Area of Trapezoid is 39 unit² . Answer
Part A:
Let the width of the rectangle be = x inches
As given, the length of a rectangle is 3 more inches than the width so let the length of the rectangle be = x+3 inches
Perimeter is given as = 54 inches
Perimeter =
Equation becomes:
=54
Part B:
Solving the equation we get
Hence, the width of the rectangle is 12 inches
Length = x+3 = 12+3 = 15 inches
Hence, length of the rectangle is 15 inches.