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3 years ago

PLEASE HELPPPPPPPPPPPPPPPPPPPP

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

8 0

Answer:

y = 5/8 x

Step-by-step explanation:

Since it goes through the origin, the y intercept is zero

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Write this as a decimal 92.8% a. 9280 b. 92.8 c. 0.928 d. 9.28

stepladder [879]

The answer would be C. 0.928.

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3 years ago

1/7 divided by what equals 14

posledela

Assume the number we are looking for in n
we want to know the value of n that makes 1/7 divided by n is 14

Transforming this to an equation:
(1/7) / n = 14
this means that:
1/7 = 14n
1 = 7 x 14n
1 = 98n
n = 1/98

Therefore:
1/7 divided by 1/98 will give us 14

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3 years ago

"The Martin family's truck gets an average of 22 miles per gallon. Predict how many miles then can drive using 3 gallons of gas.

julia-pushkina [17]

Answer: 66miles on 3 gallons of gas

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3 0

3 years ago

Determine the equation of the line that is parallel to y=5x+4 and that passes through (8,-2)

torisob [31]

Answer:

The equation of the line in slope intercept form is; y = 5x-42

Step-by-step explanation:

Parallel lines have identical or equal slopes. This implies that the form of the equation of the line will be;

y=5x+c

Since this line passes through (8,-2), we determine the value c by substituting x with 8 and y with -2. We solve the equation;

-2 =5(8)+c to obtain c = -42

The equation of the line in slope-intercept form is thus y = 5x-42

4 0

3 years ago

Read 2 more answers

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

4 years ago