![\bf \sqrt{n}< \sqrt{2n+5}\implies \stackrel{\textit{squaring both sides}}{n< 2n+5}\implies 0\leqslant 2n - n + 5 \\\\\\ 0 < n+5\implies \boxed{-5 < n} \\\\\\ \stackrel{-5\leqslant n < 2}{\boxed{-5}\rule[0.35em]{10em}{0.25pt}0\rule[0.35em]{3em}{0.25pt}2}](https://tex.z-dn.net/?f=%5Cbf%20%5Csqrt%7Bn%7D%3C%20%5Csqrt%7B2n%2B5%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bsquaring%20both%20sides%7D%7D%7Bn%3C%202n%2B5%7D%5Cimplies%200%5Cleqslant%202n%20-%20n%20%2B%205%20%5C%5C%5C%5C%5C%5C%200%20%3C%20n%2B5%5Cimplies%20%5Cboxed%7B-5%20%3C%20n%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B-5%5Cleqslant%20n%20%3C%202%7D%7B%5Cboxed%7B-5%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D0%5Crule%5B0.35em%5D%7B3em%7D%7B0.25pt%7D2%7D)
namely, -5, -4, -3, -2, -1, 0, 1. Excluding "2" because n < 2.
Answer:
For Pablo's height, just make 10% of 4 a decimal which is .4 and add 4 to it. and then for Michaela do the same which is .8 and add 4 to it so 5ft for Michaela
Answer:
cube" (and any subsequent words) was ignored because we limit queries to 32 words.
We may draw a vertical that bisects the vertex angle and the shorter side of the triangle, to form a right-triangle with the measurements:
hypotenuse = 8
length = 1.5
We may then apply:
sin(∅) = P / H
sin(∅) = 1.5 / 8
∅ = 10.8 ≈ 11°
This is half of the vertex angle, so the vertex angle is:
11 * 2 = 22°
Answer:
b po
Step-by-step explanation:
try kopo isearch mamaya sa mama ko
