10 1/5 times 5/1 add the zero
Lizzie has 18 dimes and 12 quarters
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
Given that LIzzie has 30 coins
number of dimes + number of quarters = 30
d + q = 30 ---- eqn 1
Also given that the coins total $ 4.80
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

0.1d + 0.25q = 4.8 ------ eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 30 - q ---- eqn 3
Substitute eqn 3 in eqn 2
0.1(30 - q) + 0.25q = 4.8
3 - 0.1q + 0.25q = 4.8
0.15q = 1.8
<h3>q = 12</h3>
From eqn 3,
d = 30 - 12
<h3>d = 18</h3>
Thus she has 18 dimes and 12 quarters
You'll have to move the decimal point<span> to the right as many </span>places<span> as there are zeros in the factor,then you'll have to m</span>ove the decimal point<span> one step to the right (10 has one zero),and m</span>ove the decimal point<span> two steps to the right (100 has two zeros).</span>
Step-by-step explanation:
The answer is the 2nd one, the denominator is greater than the numerator because if you add 2 AND x its gonna ge a bigger number than just x alone
Answer:
Step-by-step explanation:
Put (-6,0) and (0,3) into a table of values
form of the equation: mx+b
x -6 0
y 0 3
3/-6=-0.5 (m)
3=b (the value of y when x=0)
equation: y=0.5x+3