Answer:
Ka = 4.76108
Explanation:
- CO(g) + 2H2(g) ↔ CH3OH(g)
∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]
[ ]initial change [ ]eq
CO(g) 0.27 M 0.27 - x 0.27 - x
H2(g) 0.49 M 0.49 - x 0.49 - x
CH3OH(g) 0 0 + x x = 0.11 M
replacing in Ka:
⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)
⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)
⇒ Ka = (0.11) / (0.38)²(0.16)
⇒ Ka = 4.76108
The answer is C. They lower the activation energy of an elementary step of a reaction
This makes the reaction rate to increase since less energy is required to make a reaction occur.
Answer:
c. 0.1 M Ga₂(SO₄)₃
Explanation:
The boiling point increasing of a solvent due the addition of a solute follows the formula:
ΔT = K*m*i
<em>Where K is boiling point increasing constant (Depends of the solute), m is molality = molarity when solvent is water, and i is Van't Hoff factor.</em>
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That means the option with the higher m*i will be the solution with the highest boiling point:
a. NaCl has i = 2 (NaCl dissociates in Na⁺ and Cl⁻ ions).
m* i = 0.20*2 = 0.4
b. CaCl₂; i = 3. 3 ions.
m*i= 0.10M * 3 = 0.3
c. Ga₂(SO₄)₃ dissolves in 5 ions. i = 5
m*i = 0.10M*55 = 0.5
d. C₆H₁₂O₆ has i = 1:
m*i = 0.2M*1 = 0.2
The solution with highest boiling point is:
<h3>
c. 0.1 M Ga₂(SO₄)₃</h3>
From a Chemistry perspective it is the electron at 1/1800th the mass of a proton or neutron.
Answer:
В. No, because the mass of the reactants is less than the mass of the products.
Explanation:
Chemical equation:
NaBr + Cl₂ → 2NaCl + Br₂
The given equation is not balanced because number of moles of sodium and bromine atoms are less on reactant side while more on the product side.
There are one mole of sodium and one mole of bromine atom on left side of equation while on right side there are 2 moles of bromine and 2 moles of sodium atom are present. The number of moles of chlorine atoms are balanced.
Balanced chemical equation:
2NaBr + Cl₂ → 2NaCl + Br₂
Now equation is balanced. Number of moles of sodium , chlorine and bromine atoms are equal on both side.
