C = 11*(2*d) Try it and see that it fits every sample you have. Again this can be simplified to
C = 22 * d
Answer:
a) 0.2416
b) 0.4172
c) 0.0253
Step-by-step explanation:
Since the result of the test should be independent of the time , then the that the test number of times that test proves correct is independent of the days the river is correct .
denoting event a A=the test proves correct and B=the river is polluted
a) the test indicates pollution when
- the river is polluted and the test is correct
- the river is not polluted and the test fails
then
P(test indicates pollution)= P(A)*P(B)+ (1-P(A))*(1-P(B)) = 0.12*0.84+0.88*0.16 = 0.2416
b) according to Bayes
P(A∩B)= P(A/B)*P(B) → P(A/B)=P(A∩B)/P(B)
then
P(pollution exists/test indicates pollution)=P(A∩B)/P(B) = 0.84*0.12 / 0.2416 = 0.4172
c) since
P(test indicates no pollution)= P(A)*(1-P(B))+ (1-P(A))*P(B) = 0.84*0.88+ 0.16*0.12 = 0.7584
the rate of false positives is
P(river is polluted/test indicates no pollution) = 0.12*0.16 / 0.7584 = 0.0253
The standard deviation is 4 games
A standard deviation (or σ) is a measure of how dispersed the facts are in relation to the mean. Low general deviation method statistics are clustered around the imply, and excessive trendy deviation indicates facts are more unfold.
Don't forget the statistics set: 2, 1, 3, 2, four. The mean and the sum of squares of deviations of the observations from the mean will be 2. 4 and 5.2, respectively. as a consequence, the same standard deviation could be √(5.2/5) = 1.01.
In data, the same old deviation is a degree of the quantity of variant or dispersion of a set of values. A low preferred deviation indicates that the values tend to be close to the mean of the set, while a high general deviation shows that the values unfold out over a much broader variety.
Given that,
mean = μ = 18
standard deviation = Σ = 6
n = 2
μ x = μ = 18 games
√ x = Σ / √ = 6
√2 = 4 games
Learn more about standard deviation here brainly.com/question/12402189
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Answer:
x = 11°
Step-by-step explanation:
The parallel lines suggest we look to the relationships involving angles and transversals. The angle marked 33° and ∠CAB are alternate interior angles, hence congruent:
∠CAB = 33°
5x is the measure of the external angle opposite that internal angle and angle 2x of ΔABC, so it is equal to their sum:
5x = 2x + 33°
3x = 33° . . . . . . . . . subtract 2x
x = 11° . . . . . . . . . . . divide by 3
