i am working on this atm.
to solve you find the horizontal (x) intercepts.
so example graph A int is +3
then you find the equation where instead of f(x) etc, 0= the equation with the X value plugged in.
IE: 0=x^3-3x^2+x-3
would fit because when you simplify 0=0
0=3^3- 3(3^2)+3-3
0=27-27+3-3
0=0+0
0=0
it matches. so A would be the equation with f(x)
and continue in the same way
Use the Quadratic Formula
Three rational numbers between
1/3 and 1/5 are 4/15, 3/10, and 7/30
Given:The two numbers are 1/3 and 1/5
To find:The rational number between two numbers
Solution:Now, to find the rational number, add the numbers and divide their sum by 2.
(i) First rational number between
1/3, 1/5 = 1/3+1/5=8/5
Divide 18/5 by 2------> 8/15 x 1/2= 8/30= 4/15
The series becomes, 1/3, 4/15, 1/5
(ii) Second rational number
= 4/15+1/5 = 7/15
Divide
7/15 by 2 ------> 7/15 x 1/2 = 7/30
Hope this helps!
Referring to the above 5x=13
Then x=13/5=2.6
For y
2(2.6)+2y=0
Y= -5.2/2=-2.6
X=2.6
Y= -2.6
