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juin [17]
3 years ago
13

4. The ages of a group of tourists on a bus are 3, 6, 9, 11, 15, 26, 27, 30, 30, 31, 32. What is the standard deviation of this

tour group? * a. 10.711 O b. 11.234 O c. 114.726 O d. 126.202​
Mathematics
1 answer:
ioda3 years ago
8 0

Answer: b. 11.234

Step-by-step explanation:

used ti84

put in values in list 1

go into 1-var stats

find Sx which is the stand dev for sample

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Find the measure of angle x in the figure below: A triangle is shown. At the top vertex of the triangle is a horizontal line ali
VLD [36.1K]

Answer:

x=35^\circ

Step-by-step explanation:

From the diagram which I have drawn and attached below:

56^\circ+y+51^\circ=180^\circ$ (Sum of Angles on a Straight Line)\\y=180^\circ-(56^\circ+51^\circ)\\y=73^\circ

Next, in the triangle, the sum of the three interior angles:

y+x+72^\circ=180^\circ\\$Since y=73^\circ\\73^\circ+x+72^\circ=180^\circ\\x=180^\circ-(73^\circ+72^\circ)\\x=35^\circ

The value of angle x is 35 degrees.

7 0
3 years ago
1/8 of pizza cost 2 dollars. In an hour, 6 1/4 pizzas were sold. How much money was made at the food booth in that hour
Darina [25.2K]
First of all, you would make 6 1/4 into an improper fraction. This makes it 25/4, then you multiply it by 2 to get 50/8 and have common denominators. Divide that by 1/8, which would be 50. Then since each 1/8 costs 2 dollars you would multiply 50 by 2. So, the answer would be that they made 100 dollars.
4 0
3 years ago
Which figure is described below?
Naddika [18.5K]
Answer:
I thin’ the answer is D
8 0
3 years ago
Please help fast.
podryga [215]

\huge{\underline{\boxed{\tt{Answer:}}}}

Let AB be a chord of the given circle with centre and radius 13 cm.

Then, OA = 13 cm and ab = 10 cm

From O, draw OL⊥ AB

We know that the perpendicular from the centre of a circle to a chord bisects the chord.

∴ AL = ½AB = (½ × 10)cm = 5 cm

From the right △OLA, we have

OA² = OL² + AL²

==> OL² = OA² – AL²

==> [(13)² – (5)²] cm² = 144cm²

==> OL = √144cm = 12 cm

Hence, the distance of the chord from the centre is 12 cm.

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8 0
3 years ago
A segment in the complex plane has a midpoint at –1 + i. If the segment has an endpoint at –5 – 7i, what is the other endpoint?
morpeh [17]

Answer:

The other end point is: s+ti = 3+9i

Step-by-step explanation:

Mid-Point(M) in the complex plane states that the midpoint of the line segment joining two complex numbers a+bi and s+ti is the  average of the numbers at the endpoints.

It is given by:    M = \frac{a+s}{2} +(\frac{b+t}{2})i

Given: The midpoint = -1 + i and the segment has an endpoint at -5 - 7i

Find the other endpoints.

Let a + bi = -5 -7i  and let other endpoint s + ti (i represents imaginary )

Here, a = -5 and b = -7 to find s and t.

then;

-1+i = \frac{-5+s}{2} + ( \frac{-7+t}{2})i     [Apply Mid-point formula]

On comparing both sides

we get;

-1 = \frac{-5+s}{2}  and  1 = \frac{-7+t}{2}

To solve for s:

-1 = \frac{-5+s}{2}

or

-2 = -5+s

Add 5 to both side we have;

-2+5 = -5+s+5

Simplify:

3 = s or

s =3

Now, to solve for t;

1 = \frac{-7+t}{2}

2 =-7+t

Add 7 to both sides we get;

2+7 = -7+t+7

Simplify:

9 = t

or

t =9

Therefore, the other end point (s+ti) is, 3+9i




4 0
3 years ago
Read 2 more answers
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