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photoshop1234 [79]
2 years ago
11

Imran and Sarah share 21 sweets between them in the ratio 2:1 how many sweets does imran get

Mathematics
1 answer:
Nikitich [7]2 years ago
7 0

Answer:

14

Step-by-step explanation:

sum the parts of the ratio, 2 + 1 = 3 parts

divide the number of sweets by 3 to find the value of one part of the ratio

21 ÷ 3 = 7 sweets ← value of 1 part of the ratio , then

2 parts = 2 × 7 = 14 sweets ← Number Imran gets

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Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

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<span>6x = 6 </span>
<span>x = 1 </span>
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Answer:

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Step-by-step explanation:

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