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butalik [34]
3 years ago
13

How does confidentiality protect people and their online activity?

Computers and Technology
1 answer:
zlopas [31]3 years ago
5 0
The answer is C Explanation: process of elimination
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Which of the following does Moore's law predict?
Korolek [52]

Answer:

Hi!

The correct answer is the a.

Explanation:

The Moore's law is an a empirical law that Gordon Moore predicted doing some observations about how the density of the transistors on a integrated circuit was increasing over time.

For example, this law state that if you have an integrated circuit with: 1000 transistors in 1980 then in 1981 and six months later you will have the same integrated circuit with 2000 transistors, and so on..

  • Jan 1980: 1000 transistors.
  • Jul 1981: 2000 transistors.
  • Jan 1983: 4000 transistors.
  • Jul 1984: 8000 transistors.

And that's the reason because its cost will fall too.

7 0
3 years ago
Battery maker Duracell introduced a new product called the Duracell Powermat, which is a wireless charging pad for mobile device
lapo4ka [179]

Answer:

<em>Brand Extension </em>

Explanation:

Brand extension is using a brand name for a new product or class of product or service.

A brand extension takes advantage of a well-known product's prestige and success to start a new product.

There must be a logical link between the original product and the new item to be effective. The opposite effect, product dilution, may result from a weak or non-existent relationship.

7 0
4 years ago
Characteristics of at-risk drivers
Firlakuza [10]
An at-risk driver is someone who is recklessly driving. an at-risk driver is a driver who is driving at a very high rate of speed. an at-risk driver is a driver who is someone who is driving in dangerous way as in no seatbelt or being distracted. 
4 0
3 years ago
Read 2 more answers
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To ac
Gekata [30.6K]

Answer:

# include <iostream>

#include<stdio.h>

using namespace std;

bool IsLeapYear(int y)

int main()

{

int y;

cout<<"Enter the Year to check Leap or Not"<<endl;

cin>>y;

IsLeapYear(int y);

getch();

}

bool IsLeapYear(int y)

{

if (y%4==0)

{

   if (y%100==0)

    {

         if (y%400==0 )

         {

          cout<"The year is leap Year";

         }

         else

         {

         cout<<" The year is not Leap Year";

         }

     }

     else

     {

     cout<<"The year is Leap Year" ;

     }

}    

else

{

cout<<"The year is not Leap Year";

}    

}

Explanation:

In this program a function has been defined named as IfLeapYear, to check that whether the entered year is leap year or not. An year taken as integer data type named as y to enter the year to check. If the year is divisible by 4 but not divisible by 100 is the leap year. If the year is divisible by 4, divisible by 100 and also divisible by 400 is the century year and is also the leap year.

To check all the statements, Nested if-else conditions has been used to check multiple requirements of the leap year.

6 0
3 years ago
Read 2 more answers
The trigonometry book says: sin^2(t) + cos^2(t) = 1 Write a Python program that verifies the formula with the help of the Python
MAXImum [283]

Answer:

If you open your python-3 console and execute the following .py code you will have the following output. (Inputing 20 e.g)

Write the angles in degrees: 20

radian angles is:  0.3490658503988659

cosene( 0.3490658503988659 ) =  0.9396926207859084

sine( 0.3490658503988659 ) =  0.3420201433256687

sin^2( 0.3490658503988659 ) + cos^2( 0.3490658503988659 ) =  1.0

Explanation:

Code

import math

for i in range(1,4):

   angle = int(input('Write the angles in degrees: '))

   #mat library better works with radians

   angle_radians = (angle*math.pi)/180

   #print output

   print('radian angles is: ',angle_radians)

   print('cosene(',angle_radians,') = ',math.cos(angle_radians))

   print('sine(',angle_radians,') = ',math.sin(angle_radians))

   res = (math.sin(angle_radians))**2 + (math.cos(angle_radians))**2

   print('sin^2(',angle_radians,') + cos^2(',angle_radians,') = ',res)

6 0
3 years ago
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