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Oduvanchick [21]
3 years ago
15

A baseball team played three consecutive home games. The first game was attended by 28,453 people. The second game was attended

by 30,678 people. The third game was attended by 24,234 people.
Explain how you can round to estimate the total number of people that attended the three games.
Mathematics
1 answer:
Nataliya [291]3 years ago
6 0

Answer: it sounds like they sucked in the 1st game then in the 3r gme they played a team that doesnt suck that people like and more showed up then they suckkked even more the next game.  

Step-by-step explanation: but fr go to go0gle

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Show that a discrete metric on a vector space X≠{0} cannot be obtained from a norm (the pair (X,d) is called the discrete metric
topjm [15]

You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that

∥α(x−y)∥=|α|∥x−y∥.

But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.

Step-by-step explanation:

hope this helps

4 0
2 years ago
Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below.
garik1379 [7]

Answer:

The 95% confidence interval would be given by 0.281 \leq \mu_1 -\mu_2 \leq 0.529  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =9.2 represent the sample mean 1

\bar X_2 =8.8 represent the sample mean 2

n1=27 represent the sample 1 size  

n2=30 represent the sample 2 size  

\sigma_1 =0.3 population standard deviation for sample 1

\sigma_2 =0.1 population standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =9.2-8.8=0.4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that t_{\alpha/2}=1.96  

Now we have everything in order to replace into formula (1):  

0.4-1.96\sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}=0.281  

0.4+1.96\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=0.519  

So on this case the 95% confidence interval would be given by 0.281 \leq \mu_1 -\mu_2 \leq 0.529  

6 0
3 years ago
If 3x = 7y, what are the following ratios?<br> 3y:x
Orlov [11]

for

x

y

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y

which will give us

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while keeping the equation balance.

8 0
3 years ago
Will someone please help me with this
musickatia [10]

Answer:

B. f(-5) = -70

Step-by-step explanation:

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f(-5) = -50 - 20

f(-5) = -70

3 0
3 years ago
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Which number is equivalent to the fraction 15 over 7?
USPshnik [31]
15/7 is approximately 2.143
7 0
3 years ago
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