Answer: Final Answer
x=15,x=−15
Step-by-step explanation:
A) Isolate y in both inequalities
1) x + y ≥ 4 => y ≥ 4 - x
2) y < 2x - 3
B) Draw the lines for the following equalities:
1) y = 4 - x
2) y = 2x - 3
C) Shade the regions of solutions
1) The region that is over the line y = 4 - x
2) The region that is below the line y = 2x - 3
The solution is the intersection of both regions; this is the sector between both lines that is to the right of the intersection point, including the portion of the very line y = 4 - x and excluding the portion of the very line y = 2x - 3
Treat

as the boundary of the region

, where

is the part of the surface

bounded by

. We write

with

.
By Stoke's theorem, the line integral is equivalent to the surface integral over

of the curl of

. We have

so the line integral is equivalent to


where

is a vector-valued function that parameterizes

. In this case, we can take

with

and

. Then

and the integral becomes


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The answer is C.) x = 7; x = -6