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zaharov [31]
3 years ago
9

Which statement can be proved true using the given theorem?

Mathematics
1 answer:
Alexxx [7]3 years ago
4 0

Answer:

BF = 16

Step-by-step explanation:

18/12 = 1.5 * 6 = 9

Since DE and BF are parallel and DB and EF are parallel, they comprise a parallelogram. This means that DB = EF

DB = EF = 9

24/1.5 = 16

DE = 16

BF = 16

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A certain plant grows 1 3/4 inches every week how long will it take the plant to grow 9 1/4 inches. HELPPP I’m dumb
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It only takes 13/4 days inn week
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Figure RST on the graph is reflected over the y-axis creating figure R’S’T’. Figure R’S’T’ is translated down 2 units and left 1
Crazy boy [7]

Answer:

RST Is congruent to R’’S’’T’’

Angle R is congruent to angle R prime is congruent to angle R double-prime

TS Is congruent to T’S’ Is congruent to T’’S’’

Step-by-step explanation:

we know that

A reflection and a translation are rigid transformation that produce congruent figures

If two or more figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

Triangles RST, R'S'T and R''S''T'' are congruent

That means

Corresponding sides

RS≅R'S'≅R''S''

ST≅S'T'≅S''T''

RT≅R'T'≅R''T''

Corresponding angles

∠R≅∠R'≅∠R''

∠S≅∠S'≅∠S''

∠T≅∠T'≅∠T''

therefore

RST Is congruent to R’’S’’T’’

Angle R is congruent to angle R prime is congruent to angle R double-prime

TS Is congruent to T’S’ Is congruent to T’’S’’

3 0
3 years ago
Read 2 more answers
Please help me with all I need for tomorrow thanks
Vikentia [17]
1. 6
2. 4
3. 5
4. area
5. perimeter
6. 12
7. 16

8.

   .   . _ . _ ._.   .   .
   .   |.   .   .   |._.   .
   .   |.   .   .   .   |.  .
   .   |.   .   .   . _|.   .
   .   |. _. _. _|.   .   .

Area = 14

The borders enclose 14 squares that are 1 long and 1 unit wide.
3 0
3 years ago
The game of European roulette slots: 18 red, 18 black, and I green. A ball is spun onto the wheel and will eventually land ina s
Anestetic [448]

Answer:

(a) E(x) = -0.081  S.D = 3

(b) E(x) = -0.081  S.D = 1.73

(c) it is less risky to bet $1 in three different rounds as compared to betting $3 in a single round.    

Step-by-step explanation:

(a) You bet $3 on a single round which means that if you win the game, your amount will double ($6), your profit will be $3. Whereas, if you lose the round, your profit will be -$3. You can only bet on red or black and both have 18 slots each.

So, the probability of landing the ball in a red/black slot = 18/37. This is the probability of winning. The probability of losing can be calculated as 1-18/37 = 19/37.

We can make a probability distribution table:

x                    3             -3

P(X=x)         18/37      19/37

Expected value E(x) can be calculated as:

E(x) = ∑ x.P(x)

      = (3)(18/37) + (-3)(19/37)

E(x) = -0.081

Standard deviation can be calculated by the following formula:

Var(x) = E(x²) - E(x)²

S.D = √Var(x)

We need to first calculate E(x²).

E(x²) = ∑x².P(x)

       = (3)²(18/37) + (-3)²(19/37)

       = (9)(18/37) + (9)(19/37)

E(x²) = 9

Var(x) = E(x²) - E(x)²

         = 9 - (-0.081)²

Var(x) = 8.993

S.D = √8.993

S.D = 2.99 ≅ 3

(b) Now, the betting price is $1 and 3 rounds are played. We will compute the expectation for one round and then add it thrice to find the expectation for three rounds. Similarly, for the standard deviations, we will add the individual variances and then consider the square root of it.

E(x) = ∑ x.P(x)

      = (1)(18/37) + (-1)(19/37)

E(x) = -0.027

Standard deviation can be calculated by the following formula:

Var(x) = E(x²) - E(x)²

S.D = √Var(x)

We need to first calculate E(x²).

E(x²) = ∑x².P(x)

       = (1)²(18/37) + (-1)²(19/37)

       = (1)(18/37) + (1)(19/37)

E(x²) = 1

Var(x) = E(x²) - E(x)²

         = 1 - (-0.027)²

Var(x) = 0.9992

The expectation for one round is -0.027

For three rounds,

E(x₁ + x₂ + x₃) = E(x₁) + E(x₂) + E(x₃)

                     = (-0.027) + (-0.027) + (-0.027)

E(x₁ + x₂ + x₃) = -0.081

Similarly, the variance for one round is 0.9992.

Var (x₁ + x₂ + x₃) = Var(x₁) + Var(x₂) + Var(x₃)

                           = 0.9992 + 0.9992 + 0.9992

Var (x₁ + x₂ + x₃) = 2.9976

S.D = √2.9976

S.D = 1.73              

(c) The expected values for both part (a) and (b) are the same but the standard deviation is lower in part (c) as compared to (b). Since the standard deviation is less in part (c), it means that it is <u>less risky to bet $1 in three different rounds as compared to betting $3 in a single round.</u>            

5 0
3 years ago
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