That "ad^3" bothers me; I'm not sure what you mean here.
I'm going to assume that you have (1/4*a*d^3)^2.
If that's the case, then you have (1/4)^2 * a^2 * d^6 = (1/16)*a^2*d^6.
If this is not what you were hoping for, double check to ensure that you have copied down this problem exactly as it was presented.
A. hour worked. . . . . .. .. .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ..
Answer:
6
Step-by-step explanation:
75−3.5y−4y=4y+6
Step 1: Simplify both sides of the equation.
75−3.5y−4y=4y+6
75+−3.5y+−4y=4y+6
(−3.5y+−4y)+(75)=4y+6(Combine Like Terms)
−7.5y+75=4y+6
−7.5y+75=4y+6
Step 2: Subtract 4y from both sides.
−7.5y+75−4y=4y+6−4y
−11.5y+75=6
Step 3: Subtract 75 from both sides.
−11.5y+75−75=6−75
−11.5y=−69
Step 4: Divide both sides by -11.5.
−11.5y
−11.5
=
−69
−11.5
y=6
Hope this helps!
Answer:
42.40705%
Step-by-step explanation:
(1 - (23/100)^(19/9) = 1 + r/100
0.57593 = 1 + r/100
r = 42.40705%
