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SashulF [63]
3 years ago
7

Find the value of x​

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

need more information

Step-by-step explanation:

more information is needed to answer this question

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Explain how you would construct a perpendicular bisector of line segment WX using a compass and a straightedge.
NeX [460]

Answer:

Steps to Construct a Perpendicular Bisector of line segment \overline{WX} are as follows:

Step 1 : Draw the line segment \overline{WX} of given

             length or any length.

Step 2 : With W as center, using compass, draw a circle ( or two

              arcs one above line and one below line ) . The radius of

              circle ( or arcs ) should be more than half the length of

              \overline{WX}.

Step 3 : With the same radius and with X as center, draw

             another circle (or arcs) using compass. Let it cut the

             previous circle (or arcs) at A and B.

Step 4 : Join \overline{AB}. It cuts \overline{WX} at O.

Therefore, \overline{AB} is perpendicular bisector of \overline{WX}

4 0
3 years ago
Just to make sure, does this make sense?
Bogdan [553]

Answer:

It makes sense to me but I don't know if anyone else agrees

Step-by-step explanation:

4 0
2 years ago
Bill is 4 years older than Harris, who is 5 years old. How old is Bill? Plot Bill’s age on the number line.
il63 [147K]

Answer:

Bill is 9 years old

Step-by-step explanation:

Bill is 4 years older than 5 year old Harris. 5+4 is 9 so plot Bill on the number line as 9.

8 0
3 years ago
Read 2 more answers
for Anthony's birthday his mother is making cupcakes for his 12 friends at daycare the recipe calls for three and one third cup
charle [14.2K]
You subtract in this number sentence 
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3 years ago
In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of
Orlov [11]

Complete question is;

In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices

Answer:

Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).

Step-by-step explanation:

This is a hypothesis test for the difference between the proportions.

The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

Then, the null and alternative hypothesis are:

H0 ; π1 - π2 = 0

H1 ; π1 - π2 < 0

The significance level would be established in 0.01.

The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;

p1 = x1/n1

p1 = 43/370

p1 = 0.116

The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;

p2 = x2/n2

p2 = 23/80

p2 = 0.288

The difference between proportions is pd = (p1-p2);

pd = p1 - p2 = 0.116 - 0.288

pd = -0.171

The pooled proportion, we need to calculate the standard error, is:

p = (x1 + x2)/(n1 + n2)

p = (43 + 23)/(370 + 80)

p = 66/450

p = 0.147

The estimated standard error of the difference between means is computed using the formula:

S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]

1 - p = 1 - 0.147 = 0.853

Thus;

S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]

S_(p1-p2) = 0.044

Now, we can use the formula for z-statistics as;

z = (pd - (π1 - π2))/S_(p1-p2)

z = (-0.171 - 0)/0.044

z = -3.89

Using z-distribution table, we have the p-value = 0.00005

Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.

We conclude that The null hypothesis is rejected.

Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

6 0
3 years ago
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