Answer:
The temperature yesterday was -6 because 7-13 is -6.
Step-by-step explanation:
Answer:
![P_{Co2}= X_{Co2} P_{tot}](https://tex.z-dn.net/?f=%20P_%7BCo2%7D%3D%20X_%7BCo2%7D%20P_%7Btot%7D)
Where
represent the total pressure and
the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:
![P_{tot}= \frac{P_{Co2}}{X_{Co2}}](https://tex.z-dn.net/?f=%20P_%7Btot%7D%3D%20%5Cfrac%7BP_%7BCo2%7D%7D%7BX_%7BCo2%7D%7D)
And replacing we got:
![P_{tot}= \frac{0.31 atm}{0.46}= 0.674 atm](https://tex.z-dn.net/?f=%20P_%7Btot%7D%3D%20%5Cfrac%7B0.31%20atm%7D%7B0.46%7D%3D%200.674%20atm)
Step-by-step explanation:
For this case the partial presure of carbon dioxide is given by:
![P_{Co2}= X_{Co2} P_{tot}](https://tex.z-dn.net/?f=%20P_%7BCo2%7D%3D%20X_%7BCo2%7D%20P_%7Btot%7D)
Where
represent the total pressure and
the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:
![P_{tot}= \frac{P_{Co2}}{X_{Co2}}](https://tex.z-dn.net/?f=%20P_%7Btot%7D%3D%20%5Cfrac%7BP_%7BCo2%7D%7D%7BX_%7BCo2%7D%7D)
And replacing we got:
![P_{tot}= \frac{0.31 atm}{0.46}= 0.674 atm](https://tex.z-dn.net/?f=%20P_%7Btot%7D%3D%20%5Cfrac%7B0.31%20atm%7D%7B0.46%7D%3D%200.674%20atm)
Answer:
![\frac{x^2+2x}{x-3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%2B2x%7D%7Bx-3%7D)
Step-by-step explanation:
We need to factor out numerator and denominator in order to simplify the rational expression by cancelling common factors.
Numerator : x^3 - 4 x = x (x^2 - 4) = x (x - 2) (x + 2)
Denominator (factoring by grouping):
x^2 - 5 x + 6 = x^2 - 3 x - 2 x + 6 = x (x - 3) - 2 (x - 3) = (x - 3) (x - 2)
Then we can cancel out the common factor (x - 2) in both numerator and denominator, leading to:
x (x + 2) / (x - 3) = (x^2 + 2)/ (x-3)
![\frac{x^2+2x}{x-3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%2B2x%7D%7Bx-3%7D)