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2 years ago

Solve the formula A = one-halfbh for h

Mathematics

1 answer:

garik1379 [7]2 years ago

8 0

Answer:

$\frac{2A}{b} = h$

Step-by-step explanation:

We start with the equation $A = \frac{1}{2} bh$ . First, we multiply both sides by $2$ .

$2A = bh$

Next, we divide both sides by $b$ to get our answer:

$\frac{2A}{b} = h$

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The following table shows a proportional relationship between m and n

slavikrds [6]

Answer:

m = 7 n ( the '=' is meant to be the proportional sign)

Step-by-step explanation:

21 ÷ 3 = 7

35 ÷ 5 = 7

56 ÷ 8 = 7

7 0

3 years ago

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The square of a whole number is between 1500 and 1600. The number must be between—?

mel-nik [20]

It is 39^2 or 1521, not sure which one you want.

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3 years ago

What is the average rate of change of f over the interval -7 < or equal to x Give an exact number

Annette [7]

Answer:

$\frac{4}{3}$

Step-by-step explanation:

The average rate of change can be found by using the following formula

$\frac{f(x_{2}) - f(x_{1}) }{x_{2} - x_{1}}$

Since the interval goes from -7 to 2, we should find the y-values that correspond to x=-7 and x=2.

By inspection of the graph, we can clearly see that when x is -7, y is -7 as well and when x is 2, y is 5.

Now that we know this, we can simply plug these values into the formula!

$\frac{f(2) - f(-7) }{2 - (-7)} = \frac{5 - (-7)}{2 - (-7)} = \frac{5 +7}{2+7} = \frac{12}{9} = \frac{4}{3}$

Good luck!

3 0

2 years ago

Derivatives of inverse trigonometric functions please explain answers

Jobisdone [24]

I'll explain how to do the first one:-

y = cos-1(x2)

This can be described as ' a function of a function' x^2 is a function of x and cos-1(x^2) is a function of x^2.

We need to apply the chain rule.

Personally I find this easier to understand if i let u = x^2, so

If y = f(u) and u is a function of x then

dy/dx = dy/ du * du/dx

Here u = x^2 and y = cos-1(u)

du/dx = 2x

so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx

= -1 / √(1 - u^2) * 2x

= -2x / √(1 - u^2)

= -2x / √(1 - (x^2)^2)

= -2x / √(1 - x^4)

I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.

6 0

3 years ago

May someone please help me out with this problem? May you also explain it?

gavmur [86]

Answer:

Step-by-step explanation:

Given function is,

f(x) = $\sqrt{x}$

If the given function is vertically stretched by a scale factor of $\frac{3}{2}$ Or 1.5,

Transformed function will be,

h(x) = $\frac{3}{2}[f(x)]$

h(x) = $\frac{3}{2}(\sqrt{x})$

Further function 'h' is shifted 1 units upwards,

g(x) = h(x) + 1

g(x) = $\frac{3}{2}(\sqrt{x} )+1$

Domain of the function → x ≥ 0 Or [0, ∞)

Range of the function → y ≥ 1 Or [1, ∞)

Transformations done → Parent function f(x) is vertically stretched by a scale factor of $\frac{3}{2}$ then shifted 1 unit upward.

3 0

3 years ago