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natulia [17]
3 years ago
14

Which elements have similar behavior? barium silicon aluminum strontium osmium beryllium

Chemistry
1 answer:
victus00 [196]3 years ago
6 0

Answer:

Barium, strontium and beryllium, all belong to the group 2. Silicon belong to group 14. Aluminium belong to group 13 and Osmium belong to group 8. Hence, the elements which have similar behavior are Barium, strontium and beryllium.

Explanation:

hope this helps

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4 years ago
Read 2 more answers
1. What is the kinetic energy of 44 kg cheetah running at 31m/s speed?
Vanyuwa [196]

Explanation:

Given

mass (m) = 44 kg

velocity (v) = 31 m/s

Now

Kinetic energy

= 1/2 mv²

= 1/2 * 44 * 31²

= 0.5 * 44 * 961

= 21142 joule

Hope it will help you :)

3 0
3 years ago
I wanted known how many of the reaction below is energy released
Tema [17]

Answer:

2

Explanation:

In two reactions energy is released.

1) C₆H₁₂O₆ + 6O₂    →    6H₂O + 6CO₂ + heat

It is cellular respiration reaction.It involves the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

2) 2H₂ + O₂   →    2H₂O  ΔH = -486 kj/mol

The given reaction is formation of water. In this reaction oxygen and hydrogen react to form water and 486 kj/mol is also released.

The reaction in which heat is released is called exothermic reaction.

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂   →  CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂   →  CO₂ + 393 Kj/mol

Endothermic reactions:

The type of reactions in which energy is absorbed are called endothermic reactions.

In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.

For example:

C + H₂O   →  CO  + H₂

ΔH = +131 kj/mol

it can be written as,

C +  H₂O  + 131 kj/mol  →  CO  + H₂

5 0
3 years ago
Calculate the number of hydrogen atoms in a sample of hydrazine . Be sure your answer has a unit symbol if necessary, and round
gladu [14]

Answer:

atoms \ H= 9.767x10^{24}atoms

Explanation:

Hello!

In this case, considering that the mass of hydrazine is missing, we can assume it is 130.0 g (a problem found on ethernet). In such a way, since we need a mass-mole-atoms relationship by which we can compute moles of hydrazine given its molar mass (32.06 g/mol), then the moles of hydrogen considering one mole of hydrazine has four moles of hydrogen and one mole of hydrogen has 6.022x10²³ atoms (Avogadro's number); therefore, we proceed as shown below:

atoms \ H=130.0gN_2H_4*\frac{1molN_2H_4}{32.06gN_2H_4} *\frac{4molH}{1molN_2H_4} *\frac{6.022x10^{23}atoms}{1molH}\\\\atoms \ H= 9.767x10^{24}atoms

Notice 130.0 g has four significant figures, therefore the result is displayed with four as well.

Best regards!

7 0
3 years ago
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