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natulia [17]
3 years ago
14

Which elements have similar behavior? barium silicon aluminum strontium osmium beryllium

Chemistry
1 answer:
victus00 [196]3 years ago
6 0

Answer:

Barium, strontium and beryllium, all belong to the group 2. Silicon belong to group 14. Aluminium belong to group 13 and Osmium belong to group 8. Hence, the elements which have similar behavior are Barium, strontium and beryllium.

Explanation:

hope this helps

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What should we do to reduce the risk when working with concentrated acids and bases
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What should be done to reduce the risk when working with concentrated acids and bases are;

<em><u>1) Ensure that the concentrated acids and bases are stored separately in safety cabinets. </u></em>

<em><u>2) If you don't have separate safety cabinets and the must be stored in same cabinet, then you must ensure that they are stored in separate compartments. </u></em>

<em><u>3) Lastly, the separate compartments or cabinets must have their separate spill containment compounds.</u></em>

          When working with strong acids and bases during neutralization reactions, usually the production of gases can make the solution which is corrosive to splash and get to people around there.

         Due to how strong the acids and base are, these splashes from the neutralized solution could have potentially damaging effects on humans when it contacts them by either casing skin burns or even blindness.  

Now, to reduce the risk of the adverse effects stated above, what could be done is;

1) Ensure that the concentrated acids and bases are stored separately in safety cabinets.

2) If you don't have separate safety cabinets and the must be stored in same cabinet, then you must ensure that they are stored in separate compartments.

3) Lastly, the separate compartments or cabinets must have their separate spill containment compounds.

Read more at; brainly.com/question/17372836

5 0
2 years ago
What is a harmful role of bacteria?
zzz [600]

Answer:

sickness.

Explanation:

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6 0
4 years ago
___________ carry oxygen throughout the human body.
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Red blood cells carry oxygen throughout the human body
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Determine the energy of the electron in the 1s orbital of a helium ion (He+ )
Luda [366]
He Rydberg formula can be extended for use with any hydrogen-like chemical elements. 
<span>1/ λ = R*Z^2 [ 1/n1^2 - 1/n2^2] </span>
<span>where </span>
<span>λ is the wavelength of the light emitted in vacuum; </span>
<span>R is the Rydberg constant for this element; R 1.09737x 10^7 m-1 </span>
<span>Z is the atomic number, for He, Z =2; </span>
<span>n1 and n2 are integers such that n1 < n2 </span>
<span>The energy of a He+ 1s orbital is the opposite to the energy needed to ionize the electron that is </span>
<span>taking it from n = 1 (1/n1^2 =1) to n2 = ∞ (1/n2^2 = 0) </span>
<span>.: 1/ λ = R*Z^2 = 1.09737x 10^7*(2)^2 </span>
<span>λ = 2.278*10^-8 m </span>
<span>E = h*c/λ </span>
<span>Planck constant h = 6.626x10^-34 J s </span>
<span>c = speed of light = 2.998 x 10^8 m s-1 </span>
<span>E = (6.626x10^-34*2.998 x 10^8)/(2.278*10^-8) = 8.72*10^-18 J ion-1 </span>
<span>Can convert this value to kJ mol-1: </span>
<span>(8.72*10^-18*6.022 x 10^23)/1*10^3 = 5251 kJ mol-1 </span>
<span>Lit value: RP’s secret book: 5240.4 kJ mol-1 (difference is due to a small change in R going from H to He+) </span>
<span>So energy of the 1s e- in He+ = -5251 kJ mol-1</span>
6 0
3 years ago
For each of the following species: C2+ &amp; O2- Write the molecular orbital energy diagram and fill in the electrons Hint: in e
Tju [1.3M]

Molecular orbital energy is the energy associated with each electron in an atom or molecule.

It is expressed in electron volts (eV) and is determined by the electron's position in the atom or molecule. The molecular orbital energy diagram and fill-in the electrons are given here in each case, the number of valence electrons in the species is determined first; this is followed by the valence molecular orbital diagram for each species.

C2+: Molecular Orbital Energy Diagram

1s2 2s2 2p2

σ2s*  ← 0 e-  

σ2s   ← 2 e-

σ2p*  ← 0 e-  

σ2p   ← 0 e-

π2p*  ← 0 e-  

π2p   ← 0 e-

Bond Order: 0

Stability: Unstable

Magnetism: Diamagnetic (no unpaired electrons)

O2-: Molecular Orbital Energy Diagram

1s2 2s2 2p4

σ2s*  ← 0 e-  

σ2s   ← 2 e-

σ2p*  ← 0 e-  

σ2p   ← 2 e-

π2p*  ← 0 e-  

π2p   ← 2 e-

Bond Order: 1

Stability: Stable

Magnetism: Paramagnetic (2 unpaired electrons)

For more questions like Molecular orbital theory click the link below:

brainly.com/question/20436223

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6 0
2 years ago
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