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Arlecino [84]
2 years ago
6

What do all electrolytes have in common?

Chemistry
1 answer:
Lerok [7]2 years ago
7 0
Your answer would be they have mobile ions in solution.
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Which of these correctly defines the pOH of a solution? a.) pOH=log[H3O+] b.) pOH=-log[H30+] c.) pOH=log[OH-] d.) pOH=-log[OH-]
denis23 [38]
The answer is d) pOH = - lg[OH-]. Like pH expression: pH = -lg[H+] or pH = - lg[H3O+]. The pOH is a definition similar to the pH. So the expression is also similar. We only need to change H+ to OH-.
3 0
3 years ago
Energy has both wavelength and particle-like properties, but electrons have only particle like properties, true or false
dangina [55]

False bc both energy and electrons have both wave and particle like properties. :)

4 0
3 years ago
Why is the amount of usable energy lower for anaerobic respiration than for aerobic respiration
photoshop1234 [79]
Anaerobic is when there is not enough oxygen for aerobic respiration, so it uses glucose and lactic acid for example instead of glucose and oxygen for aerobic. Anaerobic takes longer to convert to energy. 
3 0
3 years ago
A particular sample of air is 2.5% water vapor express the concentration of water vapor in parts per million
Inessa05 [86]

Answer:

                     25000 ppm

Explanation:

<em>Parts Per Million </em>is defined as the number of parts of a solute per one million parts of a solution.

                  ppm  =  (Weight of Solute / Weight of Solution) × 10⁶   ---(1)

Let us suppose that the air (solution) weights 100 grams, then 2.5 % of water vapors will have following mass,

Mass of Vapors g / 100 g × 100  =  2.5

Or,

Mass of Vapors = 2.5 × 100 / 100

Mass of Vapors  =  2.5 g

Hence, mass of water vapors is 2.5 g.

Now, putting mass of water vapors and air in eq. 1,

                  ppm  =  (2.5 / 100) × 10⁶

                 ppm  =  25000

7 0
3 years ago
What is the total mass of products formed when 16 grams of ch4?
AlekseyPX
When CH₄ is burnt in excess O₂ following products are formed,

                           CH₄  +  2 O₂     →     CO₂  +  2 H₂O

According to equation 1 mole of CH₄ (16 g) reacts with 2 moles of O₂ to produce 1 mole of CO₂ and 2 moles of H₂O. Hence the products are,

                          1 mole of CO₂  and  2 moles of H₂O

Converting 1 mole CO₂ to grams;
As,
                           Mass  =  Moles × M.mass

                           Mass  =  1 mol ×  44 g.mol⁻¹

                           Mass  =  40 g of CO₂

Converting 2 moles of H₂O to grams,

                           Mass  =  2 mol ×  18 g.mol⁻¹
                         
                           Mass  =  36 g of H₂O

Total grams of products;

                           Mass of CO₂  =  44 g
                    +     Mass of H₂O  =  36 g
                                                  -------------
                           Total              =   80 g of Product

Result:
            80 grams of product
is formed when 16 grams of CH₄ is burnt in excess of Oxygen.
3 0
3 years ago
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