Answer:
a) 0.5198 mol/L
b) 0.00811 mol KOH
Explanation:
a) M(KOH) = 39+16+1= 56 g/mol
14.555g* 1 mol/56 g = 14.555/56 mol KOH in 500.0 mL solution
14.555/56 mol KOH ---- 0.5000 L solution
x mol KOH ----- 1 L solution
x = (14.555/56)mol * 1L/0.5000 L = 0.5198 mol/L
b) If the student pours out a 15.6 mL sample of this solution, how many moles of sodium hydroxide? (if we talk about KOH)
does the student have in the sample
15.6 mL = 0.0156 L
0.5198 mol/L * 0.0156 L = 0.00811 mol KOH
You need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. First, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. If they meet these criteria, they will have similar properties.
The first pair: Ne (Neon) and Kr (Krypton), are noble gases found in group 8
The second pair: Li (Lithium) and K (Potassium), found in group 1
The third pair: S (Sulfur) and Te (Tellurium), found in group 6
Is this a question or a statement?
I believe the answer is A. 40 mL
The correct answer among the choice listed is the third option. The reaction between silver nitrate and potassium hydroxide will yield a precipitate which is the silver hydroxide product. This is because this substance is not very soluble in aqueous solution.