What is x to this question? <br> -8 (x-1) = -32

A coyote population has decreased by 168 over the past 3 years. The same number of coyotes were lost each year. Which division e

a_sh-v [17]

Answer:

C, $\frac{-168}{3}$

Step-by-step explanation:

The number of coyotes is decreasing, which makes it negative, but you can't have a negative year, so the answer must be $\frac{-168}{3}$

6 0

3 years ago

Which of the following is the result of the equation below after completing the square and factoring? x^2-4x+2=10

Tamiku [17]

9514 1404 393

Answer:

B. (x-2)^2=12

Step-by-step explanation:

The constant that completes the square is the square of half the coefficient of the x-term. That value is (-4/2)^2 = 4.

There is already a constant of 2 on the left side of the equal sign, so we need to add 2 to both sides to bring that constant value up to 4.

x^2 -4x +2 = 10 . . . . . . . given

x^2 -4x +2 +2 = 10 +2 . . . . complete the square (add 2 to both sides)

(x -2)^2 = 12 . . . . . . . . . write as a square

6 0

3 years ago

Sixty students took a math test. The percentages of students who scored an A, B, C, or D are displayed in the circle graph, but

GarryVolchara [31]

Answer:

30

Step-by-step explanation:

8 0

2 years ago

PLS HURRY!!<br> Simplify.<br> 7/3+3(2/3−1/3)^2 Enter your answer in the box.

AveGali [126]

Do distributed property 7/3+3(2/3-1/3)^2 7/3+3×(2/3-1/3)^2 7/3+3×(1/3)^2 7/3×3×1/9 7/3×1/3 7+1/3 8/3 or 2 and 2/3 or 2.66667

3 0

3 years ago

Read 2 more answers

The following 5 questions are based on this information: An economist claims that average weekly food expenditure of households

liq [111]

Answer:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b) 2.70

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

b. 1.85

$p_v =P(Z>1.85)=0.032$

b. 0.03

a. We can reject H(0) in favor of H(a)

Step-by-step explanation:

Data given and notation

$\bar X_{1}=164$ represent the mean for the sample 1

$\bar X_{2}=159$ represent the mean for the sample 2

$\sigma_{1}=12.5$ represent the population standard deviation for the sample 1

$s_{2}=9.25$ represent the population standard deviation for the sample B2

$n_{1}=35$ sample size selected 1

$n_{2}=30$ sample size selected 2

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the expenditure of households in City 1 is more than that of households in City 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

We know the population deviations, so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-0}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Standard error

The standard error on this case is given by:

$SE=\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}$

Replacing the values that we have we got:

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b. 2.70

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

P-value

Since is a one side right tailed test the p value would be:

$p_v =P(Z>1.85)=0.032$

b. 0.03

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

a. We can reject H(0) in favor of H(a)

4 0

3 years ago

What is x to this question? -8 (x-1) = -32