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Elis [28]
3 years ago
5

The product of a number and 5

Mathematics
1 answer:
maw [93]3 years ago
3 0

Answer:

5 times the number

Step-by-step explanation:

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The following is the correct way to show the product for 0.453 × 8.1
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False

The correct product has 3+1=4 decimal digits: 3.6693
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Simplify: (2x2 − 9x + 3) + (−7x2 + 4x − 2)
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Combine like terms
2x^2 + -7x^2 = -5x^2
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Estimate the percentage: 6,683 of 20,489<br> a. 0.3% c. 3%<br> b. 43.3% d. 33.3% Explain
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Step-by-step explanation: B

6 0
2 years ago
Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

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3 years ago
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