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Lisa [10]
3 years ago
10

Given the system of the following two linear equations:

Mathematics
2 answers:
bija089 [108]3 years ago
7 0

Answer:

25/4=y

Step-by-step explanation:

Nutka1998 [239]3 years ago
3 0

thank you so much! UwU

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Tyra makes $21.40 per hour at her job for the first 40 hours and $32.10 for anything over 40 hours. if tyra typically works 45 h
Debora [2.8K]
She works for 40 hours, and then 5 hours.
So, for these first 40 hours, Tyra earns $21.40 per hour. We can find how much she earns in 40 hours:

21.40 x 40 = 856.
So, in the first 40 hours, she makes $856.

Now, for any number of hours Tayra works more that 40 hours, she will earn $32.10 each hour.

She works 5 hours over 40 hours, since it is 45 hours in total.
Hence, Tayra will earn $32.10 every hour for the 5 hours:

5 x 32.10 = 160.5.
Therefore, she will earn $160.50 for the 5 hours.

Now we have both of the earning amounts that make up how much she makes in the 45 hours. We can add them together

40 hours + 5 hours = 45 hours.
Substitute the amounts in the hours.

856 + 160.5 = 1016.5.

Thus, the answer is that Tyra will warn $1,016.50 in the total 45 hours.
Ergo, the correct answer is C.

Hope this helps, let me know if you need anything else! :)
7 0
3 years ago
Read 2 more answers
The measure of one angle in a regular octagon is
antiseptic1488 [7]

Answer:45 degrees

Step-by-step explanation:

360/8 sides =45

4 0
3 years ago
A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)=74,000+80x
SOVA2 [1]

Answer:

a) $675000

b) $289000 profit,3300 set, $190 per set

c) 3225 set, $272687.5 profit, $192.5 per set

Step-by-step explanation:

a) Revenue R(x) = xp(x) = x(300 - x/30) = 300x - x²/30

The maximum revenue is at R'(x) =0

R'(x) = 300 - 2x/30 = 300 - x/15

But we need to compute R'(x) = 0:

300 - x/15 = 0

x/15 = 300

x = 4500

Also the second derivative of R(x) is given as:

R"(x) = -1/15 < 0 This means that the maximum revenue is at x = 4500. Hence:

R(4500) = 300 (4500) - (4500)²/30 = $675000  

B) Profit P(x) = R(x) - C(x) = 300x - x²/30 - (74000 + 80x) = -x²/30 + 300x - 80x - 74000

P(x) = -x²/30 + 220x - 74000

The maximum revenue is at P'(x) =0

P'(x) = - 2x/30 + 220= -x/15 + 220

But we need to compute P'(x) = 0:

-x/15 + 220 = 0

x/15 = 220

x = 3300

Also the second derivative of P(x) is given as:

P"(x) = -1/15 < 0 This means that the maximum profit is at x = 3300. Hence:

P(3300) =  -(3300)²/30 + 220(3300) - 74000 = $289000  

The price for each set is:

p(3300) = 300 -3300/30 = $190 per set

c) The new cost is:

C(x) = 74000 + 80x + 5x = 74000 + 85x

Profit P(x) = R(x) - C(x) = 300x - x²/30 - (74000 + 85x) = -x²/30 + 300x - 85x - 74000

P(x) = -x²/30 + 215x - 74000

The maximum revenue is at P'(x) =0

P'(x) = - 2x/30 + 215= -x/15 + 215

But we need to compute P'(x) = 0:

-x/15 + 215 = 0

x/15 = 215

x = 3225

Also the second derivative of P(x) is given as:

P"(x) = -1/15 < 0 This means that the maximum profit is at x = 3225. Hence:

P(3225) =  -(3225)²/30 + 215(3225) - 74000 = $272687.5

The money to be charge for each set is:

p(x) = 300 - 3225/30 = $192.5 per set

When taxed $5, the maximum profit is $272687.5

3 0
3 years ago
Dave made fruit punch for his party but accidentally tripped and spilled 5/12 of the punch. How much of the punch was left?
QveST [7]
He still has 7/12. Because 12/12 -5/12=7/12.
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3 years ago
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Answer:

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Step-by-step explanation:

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5 0
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