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3 years ago

Don't get it at all need help

Mathematics

1 answer:

Mumz [18]3 years ago

4 0

49. Equation A
50. Equation C

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Find the midpoint of the line segment with end coordinates of: (−1,−6)and (4,5) Give coordinates as decimals where appropriate.

Arturiano [62]

Answer: The coordinates of the midpoint (1.5, -0.5)

Step-by-step explanation:

For the x-coordinate, find the difference between -1 and 4. That's 5. Take half of 5 and add to -1. So -1+2.5= 1.5

For the y-coordinate, the difference between -6 and 5 is 11. Half of 11 is 5.5. Add -6 + 5.5= 0.5

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3 years ago

3(3+4) <br> Please answer using PEMDAS And please answer correctly

DedPeter [7]

Answer:

Step-by-step explanation:

3 (7) = 21

4 0

3 years ago

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Make x the subject, fully simplify please<br>will mark brainliest <br><br>7y⁴= 7y²(z-3ax)

tekilochka [14]

Answer:

$x = \dfrac{z - y^2}{3a}$

Step-by-step explanation:

7y⁴ = 7y²(z - 3ax)

Divide both sides by 7y².

y² = z - 3ax

Add 3ax to both sides. Subtract y² from both sides.

3ax = z - y²

Divide both sides by 3a.

$x = \dfrac{z - y^2}{3a}$

5 0

3 years ago

Match the terms to their definition. 1. radical expression eliminate the radical from the denominator of a fraction 2. rationali

Vesnalui [34]

radical expression - an expression that contains a radicalrationalize - eliminate the radical from the denominator of a fractionradicand - the expression under a radical symbolrational number - a number that can be written as a ratio of two integers in the form a/b where b does not equal 0

6 0

3 years ago

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Solve this..(factorise)

Snowcat [4.5K]

Answer:

The factors are: (3a+2b +ab-6)(3a+2b -ab+6)

Step-by-step explanation:

$(a^2-4)(9-b^2)+24ab$

We need to solve the above expression using factorization.

Multiplying (a^2-4)(9-b^2)

9(a^2-4)-b^2(a^2-4) + 24ab

9a^2 -36 -a^2b^2+4b^2 + 24ab

Rearranging:

9a^2 + 4b^2 +24ab -36 -a^2b^2

We try to make perfect square of the form a^2+2ab-b^2

We have 24ab that can be written as 12ab + 12ab

Now, we can arrange the above equation:

9a^2 +12ab+ 4b^2 -(a^2b^2-12ab +36)

(3a)^2 +2(3a)(2b) + (2b)^2 -((ab)^2 -2(ab)(6)+(6)^2)

The perfect square will be:

(3a+2b)^2 - (ab-6)^2

Now We know a^2 - b^2 = (a+b)(a-b)

Here a = 3a+2b , b=ab-6

So,

(3a+2b +(ab-6))(3a+2b - (ab-6))

(3a+2b +ab-6)(3a+2b -ab+6)

So, the factors are: (3a+2b +ab-6)(3a+2b -ab+6)

3 0

3 years ago