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Fynjy0 [20]
2 years ago
13

field has a width of 70m and a length of 105m, each correct to the nearest five metres. What is the lower bound for the area of

the field, in square metres?​
Mathematics
1 answer:
Zina [86]2 years ago
8 0

Answer: Find the best estimate of the perimeter of the field.

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Complete the square to find the minimum value of the expression 4x2 + 8x + 23.
Tcecarenko [31]
So you need to come up with a perfect square that works for the x coefficients.
like.. (2x + 2)^2
(2x+2)(2x+2) = 4x^2 + 8x + 4
Compare this to the equation given. Our perfect square has +4 instead of +23. The difference is: 23 - 4 = 19

I'm going to assume the given equation equals zero..

So, If we add subtract 19 from both sides of the equation we get the perfect square.

4x^2 + 8x + 23 - 19 = 0 - 19
4x^2 + 8x + 4 = - 19
complete the square and move 19 over..
(2x+2)^2 + 19 = 0
factor the 2 out becomes 2^2 = 4
ANSWER: 4(x+1)^2 + 19 = 0

for a short cut, the standard equation
ax^2 + bx + c = 0 becomes a(x - h)^2 + k = 0
Where "a, b, c" are the same and ..
h = -b/(2a)
k = c - b^2/(4a)

Vertex = (h, k)
this will be a minimum point when "a" is positive upward facing parabola and a maximum point when "a" is negative downward facing parabola.


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3 years ago
Someone HELP (sorry if the picture is poor quality)
adoni [48]
Not sure but i would go bottom left corner answer
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The apartment building where James lives was built with bricks that total 41 10000 write this number in standard form
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larisa86 [58]
=3*5*7 (xyz)
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A fish tank has black and white fish in the ratio of 2 to 6 as shown below Which is another ratio that can describe the black to
ira [324]
1:3, Because you can simplify the numbers by dividing by two.
 
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